Grades 9–10 · English language artsAbout 150 minutes
English language artsGrades 9–10About 150 minutes

Cite precise details of a science text, summarize how it explains a complex process, and follow a multistep friction procedure with its special cases

Several sessions: close reading of the original technical text, a supervised sliding-friction measurement, modeled analysis, independent practice and a written response.

Ohio learning standards this draft targets

ela-2017:RST.9-10.1ela-2017:RST.9-10.2ela-2017:RST.9-10.2aela-2017:RST.9-10.2bela-2017:RST.9-10.3

Read the standard text

ela-2017:RST.9-10.1 Cite specific textual evidence to support analysis of science and technical texts, attending to the precise details of explanations or descriptions.

ela-2017:RST.9-10.2 Analyze content-area-specific text development.

ela-2017:RST.9-10.2a Determine the central ideas or conclusions of a text.

ela-2017:RST.9-10.2b Provide an accurate and objective summary of the central ideas of the text that traces the text's explanation or depiction of a complex process, phenomenon, or concept.

ela-2017:RST.9-10.3 Follow precisely a complex multistep procedure when carrying out experiments, taking measurements, or performing technical tasks, attending to special cases or exceptions defined in the text.

Provisional targets. Clause-by-clause educational review is still pending.

Section 1 · LearnLearn the idea
The seven steps of the invented friction procedure. Numbers in the steps: masses recorded to 0.001 kg, a fourth trial when readings differ by more than 0.2 N, added masses of 0.500 kg and 1.000 kg. Special cases defined in the text but not drawn as separate boxes: re-zero horizontally (shown in step 2), ignore the first 10 cm, record stick-slip as a range, stop near the 10 N limit, and void a trial if a mass shifts.The seven steps of the invented friction procedure. Numbers in the steps: masses recorded to 0.001 kg, a fourth trial when readings differ by more than 0.2 N, added masses of 0.500 kg and 1.000 kg. Special cases defined in the text but not drawn as separate boxes: re-zero horizontally (shown in step 2), ignore the first 10 cm, record stick-slip as a range, stop near the 10 N limit, and void a trial if a mass shifts.Friction procedure and its special cases1Measure masses to 0.001 kg2Zero the scale held horizontally3Pull level with the board4Record static peak, then steady kineticreading5Three trials; fourth if spread exceeds 0.2 N6Add one 0.500 kg mass, then a second (1.000 kgadded); repeat7Remove added masses; narrow side down; repeat
The seven steps of the invented friction procedure. Numbers in the steps: masses recorded to 0.001 kg, a fourth trial when readings differ by more than 0.2 N, added masses of 0.500 kg and 1.000 kg. Special cases defined in the text but not drawn as separate boxes: re-zero horizontally (shown in step 2), ignore the first 10 cm, record stick-slip as a range, stop near the 10 N limit, and void a trial if a mass shifts.

Learning goal: Cite specific textual evidence to support analysis of science and technical texts, attending to the precise details of explanations or descriptions; determine the central ideas or conclusions of a text; provide an accurate and objective summary that traces the text's explanation of a complex process, phenomenon or concept; and follow precisely a complex multistep procedure when carrying out experiments, taking measurements or performing technical tasks, attending to special cases or exceptions defined in the text.

Original technical text — Measuring Sliding Friction Between Two Surfaces (written for this lesson). The physics described is standard; the measurements are one class's hypothetical results.

1. What friction is. When one solid surface slides, or tends to slide, across another, each surface exerts a force on the other that acts along the surfaces and opposes the relative motion, or the motion that would occur without it. This force is friction. When the surfaces are actually sliding, it is called kinetic friction. When they are not sliding over each other, although something is tending to make them slide, it is called static friction. For a block at rest on a level board with a single horizontal push on it, static friction adjusts to match the push, up to a maximum; if the push exceeds that maximum, sliding begins.

2. What friction depends on. For many pairs of dry, rigid surfaces, such as wood on wood, the kinetic friction force is approximately proportional to the normal force, the force with which each surface presses perpendicularly on the other. The relationship is written f_k = μ_k F_N, where f_k is the kinetic friction force, F_N is the normal force and μ_k (the Greek letter mu, with subscript k for kinetic) is the coefficient of kinetic friction, a number without units that depends on the two materials and their condition. Within this model, the kinetic friction force does not depend noticeably on the apparent area of contact or, at low speeds, on the speed of sliding. These are approximations found by experiment, not laws that hold for all materials: rubber, lubricated surfaces and very high speeds depart from them.

3. Why a steady pull measures friction. If a block is pulled horizontally across a horizontal board at constant velocity, its acceleration is zero, so the net force on it is zero. Horizontally, only two forces act: the pull and kinetic friction. They must therefore be equal in size and opposite in direction. Vertically, the board's upward normal force balances the block's weight, so F_N = mg, where m is the total mass and g ≈ 9.8 N/kg near Earth's surface. Reading the pull on a spring scale during steady sliding therefore gives f_k, and dividing by mg gives μ_k. This reasoning holds only if the pull is horizontal and the speed is constant. A pull angled upward lifts part of the weight, reducing F_N, and a speeding-up block needs a pull larger than friction.

4. Procedure. Materials: a wooden block with a hook, total mass 0.500 kg, whose largest face and one narrow side are both unfinished; two 0.500 kg slotted masses and tape; a smooth wooden board at least 1 m long; a spring scale reading 0 to 10 N in 0.1 N divisions; a balance; safety goggles.
Step 1. Measure the mass of the block and each added mass on the balance; record to the nearest 0.001 kg.
Step 2. Hold the spring scale horizontally, with nothing attached, and adjust it to read zero. A scale zeroed while hanging vertically will read incorrectly when held horizontally, because the weight of its own hook and spring then pulls differently.
Step 3. Lay the board flat on the bench and the block on its largest face at one end. Attach the scale to the hook and hold it so that the scale and hook are level with the board, parallel to it.
Step 4. Pull gently and slowly. Record the highest reading just before the block starts to move; this is the maximum static friction. Then keep pulling at a slow, steady speed and record the reading during the steady middle of the slide, ignoring the first 10 cm.
Step 5. Repeat for three trials. If the three kinetic readings differ by more than 0.2 N, run a fourth and report the spread rather than discarding values without a reason.
Step 6. Tape one 0.500 kg mass centered on the block and repeat Steps 3–5; then two masses. Tape masses so they cannot slide off; if a mass shifts during a trial, that trial is void.
Step 7. With no added mass, turn the block onto its narrow side and repeat Steps 3–5 to test the effect of contact area.
Special cases. If the block moves in jerks (stick-slip) so that the reading swings rather than settling, do not average the swings; record the range, clean both surfaces with a dry cloth and try a slower pull. If any reading approaches 10 N, stop; overstretching damages the spring and the reading is no longer reliable. Wear goggles whenever a spring is stretched, and keep the masses on the bench so that none can fall.

5. One class's results (hypothetical). Largest face down: with total mass 0.500 kg (F_N = 4.9 N), kinetic trials 1.4, 1.6 and 1.5 N, mean 1.5 N, maximum static about 2.0 N; with 1.000 kg (F_N = 9.8 N), trials 2.9, 3.0 and 2.8 N, mean 2.9 N, maximum static about 3.9 N; with 1.500 kg (F_N = 14.7 N), trials 4.4, 4.3 and 4.5 N, mean 4.4 N, maximum static about 6.1 N. Narrow side down, 0.500 kg: trials 1.5, 1.4 and 1.5 N, mean about 1.5 N.

6. Conclusion. Doubling and tripling the normal force roughly doubled and tripled the kinetic friction, giving μ_k ≈ 0.30 for these surfaces, and turning the block on its side made no difference larger than the variation between trials. The results are consistent with the model in section 2 for this wood on this board; they do not show that the model holds for other materials.

Citing precise details. In a science text the details carry conditions, and the conditions are the science. Section 3 does not say "pulling a block measures friction." It says a pull measures kinetic friction "if a block is pulled horizontally across a horizontal board at constant velocity." Remove "horizontally" or "constant velocity" and the claim is false. Specific textual evidence in science therefore means quoting the qualifying words, not only the main verb. Weak: "The text says friction depends on the normal force." Strong: "Section 2 states that 'for many pairs of dry, rigid surfaces' the kinetic friction force 'is approximately proportional to the normal force,' so the relationship is presented as an approximation limited to certain surfaces, not a universal law." The strong version keeps "many," "dry, rigid" and "approximately," each of which limits the claim.

Precision also applies to numbers and units. The text gives masses in kilograms, forces in newtons and a coefficient with no unit. Citing "friction of 1.5" without "N" is incomplete, and citing μ_k with a unit is an error, because a force divided by a force has no unit.

How a science text develops. Analyzing content-area-specific text development means tracing how a text in a particular discipline builds its ideas section by section, and why that order suits the discipline. Science and technical texts commonly develop from definition, to relationship, to method, to data, to a conclusion that is deliberately narrower than the principle it began with. The friction text follows that pattern: section 1 defines friction and distinguishes kinetic from static; section 2 states the relationship f_k = μ_k F_N and its limits; section 3 develops the reasoning that justifies the method; section 4 turns that reasoning into steps; section 5 reports data; section 6 returns to the relationship and says how far the data support it. Each section depends on the one before: the procedure in section 4 makes sense only after section 3 has explained why a steady, level pull equals friction. A history text develops differently, usually by moving between events and interpretation, which is why the same reading question, how does this text develop its ideas, has a discipline-specific answer.

Central ideas and conclusions. A science text usually has a central idea (what it explains) and a conclusion (what its evidence shows). This text's central idea is that kinetic friction between dry, rigid surfaces can be measured with a horizontal steady pull and is approximately proportional to the normal force. Its conclusion, in section 6, is that for this wood on this board μ_k ≈ 0.30 and contact area made no difference beyond trial-to-trial variation, results "consistent with the model" but not proof that it holds for other materials. Notice that the conclusion is narrower than the central idea: the data concern one pair of surfaces.

An accurate, objective summary that traces a process. The complex process in this text is the reasoning in section 3: how a spring-scale reading becomes a friction force. An accurate summary keeps the steps in order and keeps their conditions. An objective summary reports what the text says without adding approval, doubt or outside facts. Model: "The text explains that when a block is pulled horizontally across a horizontal board at constant velocity, zero acceleration means zero net force, so the horizontal pull equals kinetic friction in size; vertically, the normal force equals the weight mg. The scale reading therefore gives friction, and dividing it by mg gives μ_k. The author warns that an upward-angled pull reduces the normal force and that a speeding-up block needs more pull than friction." Every clause traces a sentence in section 3, in order.

Following a complex procedure precisely. A multistep procedure is a sequence whose order and conditions exist for reasons. Following it precisely means doing each step as written, in order, and recognizing the special cases and exceptions the text defines, those situations in which the ordinary step must change. This procedure defines six: a scale zeroed vertically must be re-zeroed horizontally; the first 10 cm of a slide are ignored because the start includes the static peak and speeding up; readings spread by more than 0.2 N require a fourth trial; stick-slip motion is recorded as a range, not averaged; any reading near 10 N stops the trial; a mass that shifts during a trial voids it. Each exception protects the reasoning in section 3. The horizontal zero and the level pull keep the pull horizontal and the reading true. Ignoring the first 10 cm leaves out the readings taken while the block is starting and speeding up; it does not by itself make the rest of the slide steady, which is why Step 4 also requires a slow, steady pull and a reading from the steady middle of the slide. A reading taken while the block is still speeding up or jerking does not measure f_k, so that trial is repeated or, for stick-slip, handled as the special case says.

A fully worked model. A student's trial with 1.000 kg reads 3.6 N. Check against the procedure. The student reports holding the scale at "a slight upward angle so it would not drag." That breaks Step 3 and the condition in section 3. An upward pull lifts part of the weight, so F_N is less than 9.8 N, and only the horizontal part of the pull opposes friction. The reading no longer equals f_k, so the trial is invalid. The student also reports that the block "sped up near the end." Section 3 says a speeding-up block needs a pull larger than friction; a reading during the speeding-up part overstates f_k. The correct action is to repeat the trial with a level scale and a steady speed. The repeated trial reads 2.9 N, matching the other results.

A misconception. Many students think the "real" friction reading is the highest number the scale shows. The highest reading comes at the start and is maximum static friction, which the text asks you to record separately. Kinetic friction is the steady reading during sliding, and for these surfaces it is smaller.

Section 2 · ModelWork through the examples

Worked citation of precise detail: Question: does the text claim that friction never depends on contact area? Evidence: section 2 says that "within this model" friction "does not depend noticeably on the apparent area of contact," and adds that these are "approximations found by experiment, not laws that hold for all materials: rubber, lubricated surfaces and very high speeds depart from them." Analysis: the words "within this model," "noticeably," "apparent" and "approximations" all limit the claim, and the last sentence names exceptions. The text does not claim that area never matters; it claims that for dry, rigid surfaces the effect is too small to notice in this kind of measurement.

Worked determination of the conclusion from the data: Compute μ_k for each mass using μ_k = f_k ÷ F_N. For 0.500 kg: F_N = 0.500 × 9.8 = 4.9 N; 1.5 ÷ 4.9 ≈ 0.306. For 1.000 kg: F_N = 9.8 N; 2.9 ÷ 9.8 ≈ 0.296. For 1.500 kg: F_N = 14.7 N; 4.4 ÷ 14.7 ≈ 0.299. Mean: (0.306 + 0.296 + 0.299) ÷ 3 ≈ 0.300. The three values agree within about 0.01, which supports the text's conclusion "μ_k ≈ 0.30." Maximum static: 2.0 ÷ 4.9 ≈ 0.41, larger than μ_k; the text does not state this as a rule, but for most pairs of surfaces the static coefficient is measured larger than the kinetic one, and the reading fits that pattern. The narrow-side mean, (1.5 + 1.4 + 1.5) ÷ 3 ≈ 1.47 N, rounds to 1.5 N and differs from the largest-face result by less than the 0.2 N spread among trials, which is why the text says area "made no difference larger than the variation between trials."

Worked special case: A group's three kinetic readings with two added masses are 4.2, 4.6 and 4.4 N. The spread is 4.6 − 4.2 = 0.4 N, more than 0.2 N. Step 5 says run a fourth trial and report the spread rather than discarding values without a reason. The fourth reading is 4.4 N. The group reports mean (4.2 + 4.6 + 4.4 + 4.4) ÷ 4 = 4.4 N with a range of 4.2 to 4.6 N. They do not delete 4.6 N simply because it is highest; no procedural error was observed for that trial.

Section 3 · DoPractice, demonstrate, and explain

Procedure checklist (representation): Rewrite the procedure as a two-column checklist: the step, and the reason it is done that way, citing the sentence in section 3 or the special-case paragraph that justifies it. Add a third column in which you mark each special case or exception with the exact condition that triggers it (for example, "readings differ by more than 0.2 N").

Independent performance: Carry out the procedure with your teacher's supervision, goggles on, and with the materials available. Your teacher may approve a different block and board if both surfaces are dry and rigid, the two faces you compare have the same finish, the added masses can be taped on securely, and every pull stays well below the scale's limit; record your actual materials, how the surfaces were prepared, and your actual masses. Record every trial, including void ones and why they were void. Then write a 300- to 400-word report that (1) cites at least three precise details from the text, keeping their qualifying words; (2) states the text's central idea and its conclusion and says how they differ; (3) gives an accurate and objective summary of section 3 that traces its explanation in order; (4) computes μ_k for each normal force with the division shown; and (5) names each special case you met and what you did about it. Success criteria: all units correct and μ_k given without a unit; no step skipped or reordered without a stated reason; summary contains nothing not in the text.

Section 4 · Check7-question lesson practice test

An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.

Problem 1

Section 3 says a spring-scale reading equals the kinetic friction force. Quote the precise conditions the text attaches to that claim and explain what goes wrong if each is broken.

Show worked solution

The text says it holds 'if a block is pulled horizontally across a horizontal board at constant velocity.' If the pull is angled upward, it lifts part of the weight, reducing the normal force, and only part of the pull opposes friction. If the board is not horizontal, part of the block's weight acts along the board (helping or opposing the pull) and the normal force no longer equals mg, so neither the pull nor mg gives the right numbers. (On a tilted board the normal force has to be worked out afresh: with a pull parallel to the board it is smaller than mg, while a pull kept horizontal also presses the block into the board or lifts it, so the normal force can be smaller or larger than mg.) If the velocity is not constant, the net force is not zero: pull minus friction equals ma, so a block that is speeding up needs a pull larger than friction and a block that is slowing down reads a pull smaller than friction.

Problem 2

What is the central idea of the text, and how is its conclusion in section 6 narrower?

Show worked solution

The central idea is that kinetic friction between dry, rigid surfaces can be measured with a steady horizontal pull and is approximately proportional to the normal force. The conclusion reports that for this wood on this board μ_k ≈ 0.30 and contact area made no difference beyond trial variation, and it states that these results do not show that the model holds for other materials.

Problem 3

Write an accurate and objective summary, in two or three sentences, of how the text explains the way a scale reading becomes a friction coefficient.

Show worked solution

When a block is pulled horizontally across a horizontal board at constant velocity, zero acceleration means the net force is zero, so the pull equals kinetic friction; vertically the normal force equals the weight mg. The scale reading therefore gives f_k, and dividing it by mg gives μ_k. The text warns that an angled pull or a block that is speeding up breaks this reasoning.

Problem 4

Using the class results, calculate μ_k for the 1.500 kg trials. Show every step and state the unit, if any.

Show worked solution

F_N = mg = 1.500 kg × 9.8 N/kg = 14.7 N. The mean kinetic reading is (4.4 + 4.3 + 4.5) ÷ 3 = 4.4 N. μ_k = 4.4 N ÷ 14.7 N ≈ 0.299, which rounds to 0.30 at the two decimal places the class results support. It has no unit, because newtons divide by newtons.

Problem 5

A student zeroes the spring scale while it hangs vertically and then pulls horizontally. Which step does this break, and why does the text treat it as a special case?

Show worked solution

It breaks Step 2, which says to zero the scale while holding it horizontally. The text explains that a scale zeroed vertically reads incorrectly when horizontal because the weight of its own hook and spring pulls differently, so every reading would carry the same error.

Problem 6

During a trial the reading jumps between 1.2 N and 1.9 N and never settles. According to the text, what should the student do, and why not just average the readings?

Show worked solution

The text calls this stick-slip and says not to average the swings: record the range, clean both surfaces with a dry cloth and try a slower pull. Averaging would produce a single number that does not describe steady sliding, which is the only condition in which the pull equals kinetic friction.

Problem 7

The highest reading on the scale in the 0.500 kg trials was 2.0 N. Why does the text not use this to calculate μ_k, and what does it measure?

Show worked solution

It occurs just before the block starts to move, so it is maximum static friction, not kinetic friction. Dividing 2.0 N by 4.9 N gives about 0.41, an estimate of the static coefficient from a single reading. It is larger than μ_k ≈ 0.30, which fits the lesson's note that the steady kinetic reading is smaller than the starting peak for these surfaces.