Grade 7 Β· MathematicsAbout 120 minutes
MathematicsGrade 7About 120 minutes

Add rational numbers using opposites and directed distance

Multiple sessions using models, property-based explanations, independent rational calculations and contextual interpretation.

Ohio learning standards this draft targets

math-2017:7.NS.1math-2017:7.NS.1amath-2017:7.NS.1bmath-2017:7.NS.1d

Read the standard text

math-2017:7.NS.1 Apply and extend previous understandings of addition and subtraction to add and subtract rational numbers; represent addition and subtraction on a horizontal or vertical number line diagram.

math-2017:7.NS.1a Describe situations in which opposite quantities combine to make 0. For example, a hydrogen atom has 0 charge because its two constituents are oppositely charged.

math-2017:7.NS.1b Understand p + q as the number located a distance |q| from p, in the positive or negative direction depending on whether q is positive or negative. Show that a number and its opposite have a sum of 0 (are additive inverses). Interpret sums of rational numbers by describing real-world contexts.

math-2017:7.NS.1d Apply properties of operations as strategies to add and subtract rational numbers.

Provisional targets. Clause-by-clause educational review is still pending.

Study these connected lessons together: Subtract signed numbers and distinguish difference from distance, Justify products and quotients of signed rational numbers, Convert rational numbers to terminating or repeating decimals, Solve multistep rational-number problems and check interpretations.

Section 1 Β· LearnLearn the idea
Start at βˆ’1.5 and move 2.25 units right to 0.75. The move passes through zero after 1.5 units, with another 0.75 remaining. Start, change and final position have distinct meanings.Start at βˆ’1.5 and move 2.25 units right to 0.75. The move passes through zero after 1.5 units, with another 0.75 remaining. Start, change and final position have distinct meanings.Directed additionβˆ’4βˆ’3βˆ’2βˆ’101234βˆ’1.50.75+2.25βˆ’1.5 + 2.25 = 0.751.5 to zero, then 0.75 farther rightChange and final position are different quantities.
Start at βˆ’1.5 and move 2.25 units right to 0.75. The move passes through zero after 1.5 units, with another 0.75 remaining. Start, change and final position have distinct meanings.

Learning goal: Explain sums of signed rational numbers using zero pairs, number-line movement and properties of operations. Interpret the sign and magnitude of an addend separately and connect the result to a context.

Positive and negative quantities describe opposite directions or effects relative to a defined zero. A temperature change of +3 degrees raises a reading, while βˆ’3 degrees lowers it by the same amount. Combining those changes has zero net effect. The numbers three and negative three are additive inverses: 3 + (βˆ’3) = 0. Zero net change does not mean that no changes occurred along the way.

A counter model can represent a positive unit and a negative unit as a zero pair. If five positive counters and three negative counters are combined, three opposite pairs cancel in value, leaving two positive units. The counters are representations of signed values, not physical objects that disappear. Removing a zero pair preserves the represented sum because its combined value is zero.

The same inverse relationship applies to fractions and decimals. For example, 3/4 + (βˆ’3/4) = 0 and 1.25 + (βˆ’1.25) = 0. A zero pair's unit must be consistent: a positive half-unit and a negative whole unit do not form a zero pair. Define what each symbol represents before combining or canceling it.

Electric charge gives another situation in which opposite quantities combine to make zero. Measured in units of the proton's charge, a proton has charge +1 and an electron has charge βˆ’1. A hydrogen atom contains one of each, so its net charge is 1 + (βˆ’1) = 0. The atom is neutral although both charged particles are still present, just as a zero pair of counters has value zero without either counter vanishing.

On a horizontal number line, addition starts at the first number. The second number gives a movement whose distance is its absolute value and whose direction is determined by its sign. To calculate p + q, move |q| units from p: right for positive q and left for negative q. Absolute value describes distance from zero, so it is nonnegative; the sign supplies the direction that distance alone lacks.

For βˆ’1.5 + 2.25, start at βˆ’1.5 and move 2.25 units right. Moving 1.5 reaches zero, leaving another 0.75 to the right. The sum is 0.75. In a model where elevation relative to a platform begins at βˆ’1.5 meters and rises 2.25 meters, the final elevation is 0.75 meter above the platform. The total rise is 2.25, not 0.75; final position and change are different quantities.

For 1.5 + (βˆ’2.25), start at 1.5 and move 2.25 left. After moving 1.5 to zero, continue 0.75 to the left and end at βˆ’0.75. When addends have opposite signs, the larger magnitude determines the direction of the leftover value after opposites combine. This is an explanation for the usual calculation strategy, not a rule to memorize without reference to quantities.

Two negative addends combine in the negative direction. For βˆ’1.5 + (βˆ’0.75), start at βˆ’1.5 and move another 0.75 left to βˆ’2.25. The magnitudes add because both effects point the same way. Adding a negative number therefore need not increase a value. The word addition names the operation, not a guarantee about the size of its result.

A vertical number line represents the same reasoning with positive upward and negative downward. If a modeled temperature begins at βˆ’2 degrees and changes by +5 degrees, move five units upward to +3 degrees. The chosen zero and direction should be stated in context. An altitude model and a temperature model can share arithmetic without sharing physical units.

Properties help reorganize longer sums. The commutative property allows p + q = q + p, and the associative property allows grouping addends without changing their order of operation as additions. For (βˆ’3/4) + 2.6 + 3/4, group the opposites: [(βˆ’3/4) + 3/4] + 2.6 = 2.6. This avoids unnecessary fraction-decimal conversion while preserving the same total.

The additive identity is zero: p + 0 = p. Together, identity, inverses and regrouping provide useful strategies for exact arithmetic. Keep signs attached to their terms when rearranging. Changing βˆ’3/4 to +3/4 while moving it is not an application of commutativity; it changes the number being added.

Section 2 Β· ModelWork through the examples

Worked fractional sum: Compute βˆ’2/3 + 5/6. Express both in sixths: βˆ’4/6 + 5/6 = 1/6. Four negative sixths combine with four positive sixths, leaving one positive sixth. A number-line movement of five sixths right from negative two thirds ends at the same point.

Worked regrouping: Compute βˆ’1.25 + 4.8 + 1.25 βˆ’ 0.8 by treating the final subtraction as adding βˆ’0.8. Group βˆ’1.25 with +1.25 to make zero, and 4.8 with βˆ’0.8 to make four. The sum is four. Each rearranged term keeps its signed value.

Worked error: A student says βˆ’1.5 + 2.25 = βˆ’3.75 because one number is negative. The addends have opposite directions, so their magnitudes should partly cancel, not both contribute negatively. A rightward movement of 2.25 from βˆ’1.5 ends to the right of zero at 0.75.

Section 3 Β· DoPractice, demonstrate, and explain

Model rehearsal: Represent 5 + (βˆ’3) with five positive and three negative unit symbols, mark the zero pairs and explain the remaining value. Repeat with consistent half-unit symbols for βˆ’1 + 1.5. Then draw the same sums on a number line to connect the models rather than treating them as separate answers.

Independent performance: Create six signed-addition problems including two fractions, two decimals and one longer sum with a useful inverse pair. Solve two on a horizontal line and one on a vertical line with labeled units and equal intervals. Write a context for one sum, distinguishing start, change and final value. For the longer sum, explain exactly which property permits your regrouping and show that no term changes sign.

Section 4 Β· Check7-question lesson practice test

An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.

Problem 1

What makes two quantities additive inverses?

Show worked solution

Their sum is zero. Nonzero additive inverses have equal magnitudes and opposite signs, and zero is its own additive inverse.

Problem 2

Where does βˆ’1.5 + 2.25 end on a number line?

Show worked solution

At 0.75 after a 2.25-unit rightward move from βˆ’1.5.

Problem 3

How does a negative addend determine a number-line move?

Show worked solution

Its absolute value gives the distance and its negative sign gives the leftward or downward direction.

Problem 4

What is βˆ’2/3 + 5/6?

Show worked solution

1/6, because βˆ’2/3 equals βˆ’4/6 and βˆ’4/6 plus 5/6 leaves 1/6.

Problem 5

Why can an opposite pair be grouped first in a longer sum?

Show worked solution

Commutative and associative properties permit reordering and grouping addends, and the inverse pair sums to zero.

Problem 6

Why does zero net change not imply no events occurred?

Show worked solution

Opposite changes may have occurred and canceled in total even though the intermediate values changed.

Problem 7

A hydrogen atom has one proton with charge +1 and one electron with charge βˆ’1. What is its net charge, and what kind of situation does this illustrate?

Show worked solution

Zero, because 1 + (βˆ’1) = 0. It is a situation in which opposite quantities of equal size combine to make zero even though both are still present.