High school · ScienceAbout 180 minutes
ScienceHigh schoolAbout 180 minutes

Write and balance chemical equations to express conservation of matter, and classify reactions as exothermic or endothermic

Several sessions: a laboratory investigation, modeled examples, independent practice and a written explanation. Course level is Ohio Physical Science; topics the Ohio elaboration reserves for Chemistry or Physics are named as later work, not taught here.

Ohio learning standards this draft targets

science-2018:PS.M.5science-2018:PS.M.4

Read the standard text

science-2018:PS.M.5 Reactions of matter

science-2018:PS.M.4 Bonding and compounds

Provisional targets. Clause-by-clause educational review is still pending.

Section 1 · LearnLearn the idea
An atom inventory for the balanced combustion of methane. Carbon: 1 on each side. Hydrogen: 4 in CH₄ on the left and 2 × 2 = 4 in two water molecules on the right. Oxygen: 2 × 2 = 4 in two O₂ molecules on the left and 2 in CO₂ plus 2 in two waters, 4, on the right. Nine atoms enter and nine leave; the coefficients 1, 2, 1, 2 are the smallest whole numbers that balance it.An atom inventory for the balanced combustion of methane. Carbon: 1 on each side. Hydrogen: 4 in CH₄ on the left and 2 × 2 = 4 in two water molecules on the right. Oxygen: 2 × 2 = 4 in two O₂ molecules on the left and 2 in CO₂ plus 2 in two waters, 4, on the right. Nine atoms enter and nine leave; the coefficients 1, 2, 1, 2 are the smallest whole numbers that balance it.Atom counts for CH₄ + 2O₂ → CO₂ + 2H₂Oelementreactantsproductsbalanced?C11yesH42 × 2 = 4yesO2 × 2 = 42 + 2 = 4yes
An atom inventory for the balanced combustion of methane. Carbon: 1 on each side. Hydrogen: 4 in CH₄ on the left and 2 × 2 = 4 in two water molecules on the right. Oxygen: 2 × 2 = 4 in two O₂ molecules on the left and 2 in CO₂ plus 2 in two waters, 4, on the right. Nine atoms enter and nine leave; the coefficients 1, 2, 1, 2 are the smallest whole numbers that balance it.

Learning goal: Identify reactants and products in a chemical equation; write and balance simple equations from formulas or from a word description so that atoms of every element are conserved; explain why the formula of a product such as NaBr is fixed by ionic charges and not by the equation; and describe exothermic and endothermic reactions as transfers of thermal energy between a system and its surroundings, including why some temperature changes cannot be detected.

What an equation says. A chemical reaction rearranges atoms: the bonds in the starting substances are broken and new bonds form, producing different substances. The starting substances are the reactants, written on the left; the substances formed are the products, on the right; the arrow means "react to form". In middle school the law of conservation of matter was extended to chemical reactions: the number and type of atoms, and therefore the total mass, are the same before and after. In this course that law is expressed by writing a balanced equation, one in which every element has the same number of atoms on each side.

Coefficients and subscripts. A subscript inside a formula tells how many atoms of that element are in one unit of the substance; H₂O has two hydrogen atoms and one oxygen atom. A coefficient in front of a formula tells how many units take part; 2H₂O means two water molecules, four hydrogen atoms and two oxygen atoms in all. Balancing is done only with coefficients. Changing a subscript changes the substance: H₂O₂ is hydrogen peroxide, not "two waters", and writing it to make the counts work describes a different reaction. An equation is balanced when, for every element, the count on the left equals the count on the right, and the coefficients are the smallest whole numbers that do it.

A method that works. Write the correct formulas first. Count atoms of each element on each side. Balance elements that appear in only one substance on each side first, saving any element that appears in several places, often oxygen or hydrogen, for last. Adjust coefficients, recount and repeat. Worked model, methane burning in oxygen: CH₄ + O₂ → CO₂ + H₂O. Counts: left C 1, H 4, O 2; right C 1, H 2, O 3. Carbon is balanced. Hydrogen: put 2 in front of H₂O, giving H 4 on the right and O now 2 + 2 = 4 on the right. Oxygen: put 2 in front of O₂, giving O 4 on the left. Final: CH₄ + 2O₂ → CO₂ + 2H₂O, with C 1 = 1, H 4 = 4, O 4 = 4. Reading it: one methane molecule and two oxygen molecules react to form one carbon dioxide molecule and two water molecules, and nine atoms go in and nine come out. Relationships beyond these coefficients, and sorting reactions into named types, are chemistry topics; here the skill is to write, balance and read.

Formulas come first and do not bend. Students often ask why sodium reacting with bromine gives NaBr rather than NaBr₂, since bromine comes as Br₂ molecules. The formula of the product is fixed by the ions: sodium in group 1 forms Na⁺ and bromine in group 17 forms Br⁻, and the charges cancel one to one, so the compound is NaBr. Balancing then handles the Br₂ with a coefficient: 2Na + Br₂ → 2NaBr. Two sodium atoms each give one electron to one of the two bromine atoms, making two Na⁺ and two Br⁻. NaBr₂ would need a sodium ion with a 2+ charge, which sodium does not form. The general lesson is that the identity and formula of each substance is decided by the chemistry of the elements, and only the coefficients are adjustable.

Word descriptions to equations. "Magnesium metal burns in oxygen to form magnesium oxide": magnesium is Mg, oxygen gas is O₂, and the ionic product from Mg²⁺ and O²⁻ is MgO, so Mg + O₂ → MgO, balanced as 2Mg + O₂ → 2MgO. "Hydrogen gas and chlorine gas form hydrogen chloride": H₂ + Cl₂ → 2HCl. Elements that exist as two-atom molecules (the gases hydrogen, nitrogen, oxygen, fluorine and chlorine, plus liquid bromine and solid iodine) are written with the subscript 2 as reactants; metals and most other solids are written as single symbols.

Energy in reactions. Every reaction involves energy as well as atoms. Breaking bonds requires energy and forming bonds releases it, and the net result is a transfer of thermal energy between the reacting system and its surroundings. If the system releases thermal energy to the surroundings, the reaction is exothermic and the surroundings warm: a burning match, a chemical hand warmer, the reaction that sets concrete. If the system absorbs thermal energy from the surroundings, it is endothermic and the surroundings cool: an instant cold pack, or baking soda reacting with vinegar, whose mixture cools by a few degrees. Whether the change can be noticed depends on how much energy moves and how large the surroundings are. A hand warmer is warm to the touch, with no instrument. The baking soda and vinegar reaction cools only a few degrees, observable with a thermometer but not by hand. A nail rusting releases thermal energy too, but so slowly and into such large surroundings that the temperature change is too small to detect with a classroom thermometer; the energy is real but undetectable with that equipment. Saying a reaction "has no energy change" because nothing felt warm is the misconception to avoid.

Investigation: conservation of mass and energy transfer. Materials: a clean, empty 500 mL plastic bottle made for carbonated drinks, with its screw cap; about 1 g of baking soda folded into a small square of tissue; about 20 mL of vinegar; a small funnel; a balance reading to 0.1 g; a small open cup; a thermometer or probe; goggles. Part A, mass: pour the vinegar into the bottle through the funnel, put the capped bottle and the tissue packet on the balance together and record the total mass; drop the packet into the bottle and screw the cap on at once; swirl gently until the fizzing stops and record the mass of the capped bottle; then loosen the cap slowly, pointing the bottle away from faces, let the gas escape, retighten and record the mass again. Part B, energy: in the open cup, stir about 1 g of baking soda into 20 mL of vinegar with the thermometer in the liquid and record the starting and lowest temperatures. Record: mass before, mass after while capped, mass after opening, starting and lowest temperature. A result that supports the claims: the capped mass is the same before and after within the balance's precision, showing the atoms were conserved even though a gas formed; the mass falls after opening because carbon dioxide escaped, not because matter was destroyed; the temperature in the cup falls by a few degrees, showing the reaction is endothermic. A rigid bottle is used on purpose rather than a zip-seal bag: a bag that swells by about a liter is pushed up by the extra air it displaces, which can make a sealed bag read about 1 g lighter on a balance even though no matter has left it. Safety: goggles; use only a plastic bottle designed for carbonated drinks, never glass, and no more than the stated amounts, which build only a modest pressure; open the cap slowly. What the model cannot show: the bottle demonstrates conservation for one reaction but cannot show the individual atoms rearranging, and the thermometer measures only the mixture, so it cannot say how much energy moved, only that the reacting system took thermal energy from its surroundings.

Section 2 · ModelWork through the examples

Worked example 1 — balance from formulas. Aluminum reacts with chlorine: Al + Cl₂ → AlCl₃. Counts: left Al 1, Cl 2; right Al 1, Cl 3. Chlorine is 2 on the left and 3 on the right, so find a common count of 6: 3Cl₂ on the left and 2AlCl₃ on the right. Now Al is 2 on the right, so 2Al on the left. Final: 2Al + 3Cl₂ → 2AlCl₃; check Al 2 = 2, Cl 6 = 6. The formula AlCl₃ was given and was never changed.

Worked example 2 — balance a combustion. Propane burns: C₃H₈ + O₂ → CO₂ + H₂O. Carbon: 3 on the left, so 3CO₂. Hydrogen: 8 on the left, so 4H₂O. Oxygen on the right is now 3 × 2 + 4 × 1 = 10, so 5O₂ on the left. Final: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O; check C 3 = 3, H 8 = 8, O 10 = 10. Oxygen was left until last because it appears in two products.

Worked example 3 — from a word description. "Hydrogen gas reacts with oxygen gas to form water." Formulas: H₂, O₂, H₂O. Unbalanced: H₂ + O₂ → H₂O has O 2 on the left and 1 on the right. Put 2 in front of H₂O: O balanced at 2, but H is now 4 on the right, so 2H₂ on the left. Final: 2H₂ + O₂ → 2H₂O. The counts are H 4 = 4 and O 2 = 2, and the coefficients 2, 1, 2 cannot be reduced. This is a representation on paper; the real reaction is explosive and is never done by students.

Worked example 4 — classify by energy transfer and by detectability. A camping stove burning is exothermic, and the transfer is obvious without an instrument. Baking soda with vinegar is endothermic; a thermometer shows a drop of a few degrees that a hand would miss. Iron slowly rusting in a garage is exothermic, but the energy leaks into such large surroundings over months that no thermometer detects a change; the direction of transfer is known from faster versions of the same reaction (the iron in a hand warmer rusting quickly gets hot). The classification is about direction of energy transfer between system and surroundings, not about whether it is easy to notice.

Section 3 · DoPractice, demonstrate, and explain

Representation task: an atom inventory. For the equation 2Mg + O₂ → 2MgO, draw the reactants and products as labeled circles (Mg and O), then complete a two-column table counting Mg and O atoms on each side. Repeat for CH₄ + 2O₂ → CO₂ + 2H₂O with three rows (C, H, O). Under each table write one sentence stating what the equal counts show and one sentence saying what a coefficient means that a subscript does not.

Independent performance: write, balance and report on a reaction. Choose one safe reaction you can observe, for which the teacher supplies the formulas of the reactants and products: baking soda with vinegar (NaHCO₃ + CH₃COOH → NaCH₃COO + H₂O + CO₂), steel wool rusting in a hand warmer (Fe + O₂ → Fe₂O₃, to be balanced), or a teacher-provided alternative. Success criteria: the balanced equation is written with correct formulas and a table showing each element's count on both sides; the ionic products' formulas are justified from the group charges where the elements come from groups 1, 2, 17, hydrogen or oxygen; the reaction is classified as exothermic or endothermic from a recorded temperature measurement with the starting and ending readings stated; the report names one example of a reaction whose temperature change is too small to detect with a classroom thermometer and explains why in terms of the size of the surroundings; and one paragraph explains what a sealed-container mass measurement would show and why an open container gives a different result.

Section 4 · Check7-question lesson practice test

An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.

Problem 1

Balance Fe + O₂ → Fe₂O₃ and show the atom count that proves it.

Show worked solution

Oxygen: 2 on the left and 3 on the right, so use 3O₂ and 2Fe₂O₃ to get 6 each. Iron is then 4 on the right, so 4Fe on the left. Balanced: 4Fe + 3O₂ → 2Fe₂O₃. Count: Fe 4 = 2 × 2 = 4; O 3 × 2 = 6 = 2 × 3 = 6. Only coefficients were changed; the formula Fe₂O₃ stayed as given.

Problem 2

Why does sodium reacting with bromine produce NaBr and not NaBr₂, even though bromine is Br₂?

Show worked solution

The formula of the product is fixed by the ions, not by the reactant molecules. Sodium in group 1 forms Na⁺ and bromine in group 17 forms Br⁻, and one of each cancels the charge, so the compound is NaBr; NaBr₂ would require Na²⁺, which sodium does not form. The Br₂ is handled by balancing with coefficients: 2Na + Br₂ → 2NaBr, two sodium atoms each giving one electron to one bromine atom.

Problem 3

Explain the difference between changing a coefficient and changing a subscript when balancing, using H₂O and H₂O₂.

Show worked solution

A coefficient in front of a formula multiplies the whole unit: 2H₂O is two water molecules, still water. A subscript is part of the formula: changing H₂O to H₂O₂ turns water into hydrogen peroxide, a different substance with different properties. Balancing must preserve the identity of every substance, so only coefficients may be changed; altering a subscript writes an equation for a different reaction.

Problem 4

Write and balance the equation for calcium reacting with chlorine gas to form calcium chloride, justifying the product's formula.

Show worked solution

Calcium is a group 2 metal forming Ca²⁺; chlorine is a group 17 nonmetal forming Cl⁻, so two chloride ions per calcium ion give CaCl₂. Chlorine gas is Cl₂. The equation Ca + Cl₂ → CaCl₂ already balances: Ca 1 = 1, Cl 2 = 2. The formula was decided by charges first, then the atom count was checked.

Problem 5

A student mixes baking soda and vinegar and the thermometer drops from 21.0 °C to 17.5 °C. Classify the reaction and describe the direction of energy transfer.

Show worked solution

The temperature of the mixture fell by 3.5 °C, so the reacting system absorbed thermal energy from its surroundings, including the liquid, the container and the thermometer. That makes the reaction endothermic. Energy moved from surroundings into the system; the surroundings cooled. The change was too small to detect reliably by touch but clear with a thermometer.

Problem 6

Give one example each of a reaction whose temperature change is observable without an instrument, observable only with a thermometer, and too small to detect with a classroom thermometer, and explain the third case.

Show worked solution

Without an instrument: a burning match or a chemical hand warmer, which is clearly hot. With a thermometer: baking soda and vinegar, which cools by a few degrees. Too small to detect with a classroom thermometer: a nail rusting over months. The rusting releases thermal energy, but so slowly and into such a large volume of air and ground that the surroundings' temperature never changes measurably; a reaction's energy transfer is real even when it cannot be detected by temperature.

Problem 7

In a capped plastic bottle, baking soda and vinegar produce gas and the mass reads the same before and after. When the cap is loosened the mass drops. Explain both observations.

Show worked solution

Capped, no matter can enter or leave, so every atom present before the reaction is still present afterward, rearranged into new substances including carbon dioxide gas; the equal masses show conservation of matter. Loosening the cap lets the carbon dioxide escape into the air, so the bottle now holds fewer atoms and reads less. Matter was not destroyed; it left the container.