Describe the effect of dilations, translations, rotations and reflections on figures using coordinates
Several sessions: tracing-paper or transparency experiments, coordinate work, modeled examples, independent practice and a written argument.
Ohio learning standards this draft targets
math-2017:8.G.3
Read the standard text
math-2017:8.G.3 Describe the effect of dilations, translations, rotations, and reflections on two-dimensional figures using coordinates.
Provisional targets. Clause-by-clause educational review is still pending.
πSection 1 Β· LearnLearn the idea
Triangle A(2, 1), B(6, 1), C(3, 4) under seven coordinate rules. Side AB has length 4 in the pre-image and in every rigid-motion image; the dilation with k = 2 gives Aβ²(4, 2), Bβ²(12, 2), so Aβ²Bβ² = 8, and the dilation with k = 1/2 gives Aβ²Bβ² = 2. Under the 90Β° counterclockwise rotation C(3, 4) goes to (β4, 3), still 5 units from the origin.
Learning goal: Write the coordinate rule for translations, reflections across an axis, rotations about the origin and dilations centered at the origin, apply each rule to every vertex of a figure, and describe in words what the transformation does to the figure's position, size, orientation and shape.
Why coordinates. A drawing shows roughly what a transformation does; coordinates say exactly. Each transformation below has a rule of the form (x, y) β (something, something). Apply the rule to every vertex of a polygon, then connect the image vertices in the same order. The rules apply to points, so a figure with five vertices needs the rule applied five times.
Translation by a units horizontally and b units vertically: (x, y) β (x + a, y + b). Positive a moves right, negative a moves left; positive b moves up, negative b moves down. Effect: the image is congruent to the pre-image, in the same orientation, with every side still parallel to its original, just moved.
Reflection across the x-axis: (x, y) β (x, βy). The x-coordinate is unchanged because the point moves straight up or down onto the perpendicular through its own x; the y-coordinate changes sign because the image is the same distance from the axis on the other side. Reflection across the y-axis: (x, y) β (βx, y), for the same reason with the roles swapped. Effect: congruent image, orientation reversed. These two rules are only for the axes; reflecting across some other line has a different rule.
Rotation about the origin. A quarter turn counterclockwise takes (1, 0) to (0, 1) and (0, 1) to (β1, 0). The box with corners at the origin and (x, y) turns with the point, so 90Β° counterclockwise is (x, y) β (βy, x). Two quarter turns make a half turn: 180Β° is (x, y) β (βx, βy), the same in either direction. 90Β° clockwise is a quarter turn the other way, (x, y) β (y, βx), which is also 270Β° counterclockwise. Effect: congruent image, same orientation, turned. These rules are for the origin as center; a rotation about another point has a different rule.
Dilation centered at the origin with scale factor k (k positive): (x, y) β (kx, ky). Each point moves along the ray from the origin through it, to k times its original distance from the origin. If k is greater than 1 the image is an enlargement; if k is between 0 and 1 it is a reduction; k = 1 leaves everything fixed. Effect: the image has the same shape and the same angles, every length is multiplied by k, and every area is multiplied by kΒ². A dilation with k β 1 is not a rigid motion, because it changes lengths; its image is similar to the pre-image, not congruent. With k = 1 the dilation is the identity: nothing moves, and the image is the pre-image itself. The center itself does not move, so a figure not containing the origin also moves away from or toward the origin as it grows or shrinks.
A worked model. Triangle ABC has A(2, 1), B(6, 1), C(3, 4). Side AB is horizontal, length 4. Apply each rule to all three vertices.
Translation (x, y) β (x + 2, y β 3): Aβ²(4, β2), Bβ²(8, β2), Cβ²(5, 1). Check C: 3 + 2 = 5 and 4 β 3 = 1. Aβ²Bβ² is still horizontal with length 8 β 4 = 4.
Reflection across the x-axis (x, βy): Aβ²(2, β1), Bβ²(6, β1), Cβ²(3, β4). The triangle now hangs below the axis; Aβ²Bβ² has length 4.
Reflection across the y-axis (βx, y): Aβ²(β2, 1), Bβ²(β6, 1), Cβ²(β3, 4). Note that Bβ² is now the leftmost point: the reflection reversed left and right.
Rotation 90Β° counterclockwise (βy, x): Aβ²(β1, 2), Bβ²(β1, 6), Cβ²(β4, 3). Check C(3, 4): its distance from the origin is 5, the diagonal of a 3-by-4 box; Cβ²(β4, 3) is the diagonal of a 4-by-3 box, also 5, and its direction has turned a quarter turn. Aβ²Bβ² is now vertical, from height 2 to height 6, length 4.
Dilation, center the origin, k = 2: (2x, 2y): Aβ²(4, 2), Bβ²(12, 2), Cβ²(6, 8). Aβ²Bβ² has length 12 β 4 = 8, which is 2 Γ 4. A is β5 units from the origin (a 2-by-1 box) and Aβ² is β20 = 2β5 units away: twice as far, on the same ray.
Dilation, k = 1/2: Aβ²(1, 0.5), Bβ²(3, 0.5), Cβ²(1.5, 2). Aβ²Bβ² has length 2, half of 4.
Describing the effect in words. Coordinates are the evidence; the description is the conclusion. For the translation: "a congruent triangle, 2 units right and 3 units down, same orientation." For the 90Β° rotation: "a congruent triangle turned a quarter turn counterclockwise about the origin; the horizontal side became vertical." For the dilation by 2: "a similar triangle with every side doubled, every angle unchanged, and every vertex twice as far from the origin." Say what changed and what did not.
Recognizing a rule from coordinates. If every image coordinate is the pre-image coordinate plus the same constants, it is a translation. If one coordinate is unchanged and the other has changed sign, it is a reflection across an axis. If both changed sign, a 180Β° rotation. If the coordinates swapped places with one sign change, a 90Β° rotation; look at where (1, 0) would go to decide the direction. If both coordinates are multiplied by the same positive number, a dilation centered at the origin.
Misconceptions. The commonest error is mixing up the two 90Β° rules. Test the rule you wrote on the point (1, 0): counterclockwise must send it to (0, 1), clockwise to (0, β1). A second error is applying the rule to some vertices and copying the rest by eye; the image will be a slightly wrong shape. A third is treating a dilation as a slide: the image of a dilation is a different size, and the points nearer the origin move less than the points farther away.
βοΈSection 2 Β· ModelWork through the examples
Worked dilation of a rectangle: Rectangle with vertices (1, 1), (3, 1), (3, 2), (1, 2) is dilated from the origin with k = 3. Rule (3x, 3y): (3, 3), (9, 3), (9, 6), (3, 6). The 2-unit side became 9 β 3 = 6 units and the 1-unit side became 6 β 3 = 3 units, both multiplied by 3. The area went from 2 Γ 1 = 2 square units to 6 Γ 3 = 18 square units, multiplied by 3Β² = 9. The angles are still right angles.
Worked rotations of one point: Rotate (β2, 5) about the origin. 90Β° clockwise, (y, βx): (5, 2). 90Β° counterclockwise, (βy, x): (β5, β2). 180Β°, (βx, βy): (2, β5). All four points are the same distance from the origin, the diagonal of a 2-by-5 box, which is what a rotation about the origin must keep.
Worked identification: Pre-image (1, 2), (4, 2), (4, 6). Image 1: (β1, 2), (β4, 2), (β4, 6). Each y is unchanged and each x has changed sign: a reflection across the y-axis. Image 2: (2, 4), (8, 4), (8, 12). Each coordinate has been doubled: a dilation centered at the origin with k = 2; the vertical side grew from 4 to 8. Image 3: (β2, 1), (β2, 4), (β6, 4). Each (x, y) became (βy, x): a 90Β° counterclockwise rotation; check (1, 2) β (β2, 1).
Worked sequence: Apply (x, y) β (x β 5, y + 2) and then reflect across the x-axis to the point (3, 1). First (3 β 5, 1 + 2) = (β2, 3), then (β2, β3). Doing the reflection first gives (3, β1) and then (β2, 1), a different point, so the order must be stated.
Recording task: Make a table with the vertices A(2, 1), B(6, 1), C(3, 4) as its column headings and one row for each of the seven rules in the lesson: translation (x + 2, y β 3), reflection across the x-axis, reflection across the y-axis, rotation 90Β° counterclockwise, rotation 180Β°, dilation k = 2 and dilation k = 1/2. Fill every cell by applying the rule, then plot two of the rows on a grid and check by eye that the drawn image matches the description in words (moved, flipped, turned or resized).
Independent performance: Choose a quadrilateral with vertices on grid points, none on either axis, and with at least one side that is neither horizontal nor vertical. Apply all seven rules from the recording task and, for each, compute the length of one slanted side (neither horizontal nor vertical) before and after from its run and rise, and state in one sentence the effect on position, size and orientation. Success criteria: every image coordinate is correct when a partner tests the rule on one vertex; the side length is unchanged for the five rigid motions and multiplied by exactly k for the two dilations; the 90Β° counterclockwise rule is confirmed by testing it on (1, 0), which must go to (0, 1), and the clockwise rule (y, βx) is written beside it for contrast; and the sentences use the words congruent or similar correctly.
β Section 4 Β· Check8-question lesson practice test
An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.
Problem 1
Find the image of (β3, 4) under a rotation of 180Β° about the origin, and explain the rule.
Show worked solution
The rule is (x, y) β (βx, βy), so the image is (3, β4). A half turn sends a point to the opposite side of the origin at the same distance: (β3, 4) is 3 left and 4 up, and (3, β4) is 3 right and 4 down. Both are 5 units from the origin, the diagonal of a 3-by-4 box.
Problem 2
The segment from (4, 6) to (4, β2) is dilated from the origin with k = 1/2. Give the image and compare the lengths.
Show worked solution
Rule (x/2, y/2): (2, 3) and (2, β1). The original segment is vertical with length 6 β (β2) = 8. The image is vertical with length 3 β (β1) = 4. The length was multiplied by 1/2, as a dilation with k = 1/2 requires, and the image is still vertical because the dilation does not change directions.
Problem 3
Write the rule for a rotation of 90Β° counterclockwise about the origin and test it on (1, 0) and on (5, 2).
Show worked solution
The rule is (x, y) β (βy, x). Test: (1, 0) β (0, 1), which is a quarter turn counterclockwise from pointing right to pointing up, so the direction is correct. Then (5, 2) β (β2, 5). Both points are the same distance from the origin, the diagonal of a 5-by-2 box, so the rotation kept the distance as it must.
Problem 4
Reflect the triangle with vertices (1, β1), (4, β1) and (1, β3) across the x-axis. Give the image vertices and describe the effect on side lengths, angles, orientation and position.
Show worked solution
The rule is (x, y) β (x, βy), so the image is (1, 1), (4, 1), (1, 3). Side lengths are unchanged: the horizontal side is 3 units and the vertical side 2 units in both, and the slanted side keeps its run 3 and rise 2. The angles are unchanged, including the right angle at (1, β1), which becomes the right angle at (1, 1). The orientation is reversed: (1, β1) β (4, β1) β (1, β3) turns clockwise, while the image read in the same order turns counterclockwise. The position changes from below the x-axis to the mirror position above it. The image is congruent to the pre-image.
Problem 5
A triangle is translated by (x, y) β (x β 4, y + 1). Describe the effect on its side lengths, angles and orientation.
Show worked solution
None of them change. Every vertex moves 4 left and 1 up, so every side keeps its run and rise and therefore its length and direction; the angles between the sides are unchanged; the vertices are still read in the same turning direction. The only change is position: the image is a congruent copy 4 units left and 1 unit up.
Problem 6
Pre-image (2, 2), (6, 2), (6, 5); image (1, 1), (3, 1), (3, 2.5). What single transformation was applied? Justify with a check.
Show worked solution
Each image coordinate is exactly half the pre-image coordinate, so it is a dilation centered at the origin with k = 1/2. Check: (6, 5) β (3, 2.5). The horizontal side went from 4 to 2 units and the vertical side from 3 to 1.5 units, both halved, and the right angle is unchanged. The image is similar to the pre-image, not congruent.
Problem 7
Does the dilation (x, y) β (3x, 3y) move the point (0, 0)? What happens to (1, 0) and to (2, 0)?
Show worked solution
(0, 0) β (0, 0): the center of the dilation is fixed. (1, 0) β (3, 0), moving 2 units; (2, 0) β (6, 0), moving 4 units. Points farther from the center move farther, which is why a dilation is not a slide. Every point ends up 3 times as far from the origin, along the same ray.
Problem 8
A student rotates (2, 5) by 90Β° clockwise about the origin and writes (β5, 2). Identify the error and give the correct image.
Show worked solution
The student used (βy, x), which is the counterclockwise rule. Test on (1, 0): it gives (0, 1), pointing up, which is counterclockwise from pointing right. Clockwise is (x, y) β (y, βx), so (2, 5) β (5, β2). The studentβs answer is the image under the opposite turn.