Grade 7 · ScienceAbout 180 minutes
ScienceGrade 7About 180 minutes

Separate mixtures and explain mass and volume evidence

Atom modeling and repeated measurements support an independent explanation or separation design.

Ohio learning standards this draft targets

science-2018:7.PS.2

Read the standard text

science-2018:7.PS.2 Matter can be separated or changed, but in a closed system, the number and types of atoms remains constant.

Provisional targets. Clause-by-clause educational review is still pending.

Study these connected lessons together: Conserve atom inventories when substances form new arrangements, Classify elements with property evidence and select materials.

Section 1 · LearnLearn the idea
Invented dry-mass account for a 20 g starting mixture: 9.8 g gravel, 7.6 g sand and 1.7 g sugar recovered; 0.9 g unaccounted in the current recovery record. The whole remains 20 g, and added water is recorded separately.Invented dry-mass account for a 20 g starting mixture: 9.8 g gravel, 7.6 g sand and 1.7 g sugar recovered; 0.9 g unaccounted in the current recovery record. The whole remains 20 g, and added water is recorded separately.Invented dry recovery · whole starts at 20 gRecovered fractions plus unaccounted remainderGravel recovered: 9.8 gSand recovered: 7.6 gSugar recovered: 1.7 gUnaccounted: 0.9 g9.8 + 7.6 + 1.7 + 0.9 = 20 gUnaccounted is not a new ingredient.Added water has a separate input record.
Invented dry-mass account for a 20 g starting mixture: 9.8 g gravel, 7.6 g sand and 1.7 g sugar recovered; 0.9 g unaccounted in the current recovery record. The whole remains 20 g, and added water is recorded separately.

Learning goal: Design a separation using differences in material properties, distinguish solutions, suspensions and colloids, and keep a complete mass account while explaining why mixed volumes need not add.

A mixture contains two or more substances together without requiring them to form one new compound with a single fixed composition. In sugar water, sugar molecules disperse among water molecules while retaining their identities. The dissolved sugar has not vanished or turned into water. The amount of sugar can vary from sample to sample, unlike the fixed atom ratio in the formula for a particular compound.

A solution has dissolved particles distributed throughout the mixture on a very small scale. A suspension contains larger dispersed particles that can settle under appropriate conditions; muddy water provides a familiar example. A colloid has dispersed particles that do not readily settle like those in a typical suspension; milk is a familiar complex example. Appearance alone cannot reliably identify every mixture. Cloudiness, settling, filtration behavior and reference information provide different pieces of evidence.

An ordinary paper filter can retain particles larger than its effective openings, but dissolved sugar passes with the water. Therefore a clear filtrate does not establish that it is pure water. Settling followed by careful pouring can separate some suspended material; a sieve can separate sufficiently different particle sizes. A magnet can separate a magnetic component from a nonmagnetic one when the materials and geometry permit it. Choose a process by a tested property, not because every mixture should use the same procedure.

For a teacher-supplied mixture of clean gravel, sand and a small amount of sugar, propose a sequence before acting. Sieve out the gravel with an opening size checked against the particles. Add a measured amount of water to the remaining material and stir to dissolve the sugar. Filter to retain sand. Pour all of the filtered sugar solution into a shallow labeled dish and allow it to evaporate at room temperature in a protected classroom location. The water enters surrounding air while sugar remains; this last container is an open system.

If recovering water is part of the goal, simple evaporation into room air is insufficient. Water vapor would need to be collected and condensed using suitable teacher-provided apparatus. Decide whether the design aims to recover every component or only selected ones. Do not describe a partly recovered mixture as fully separated into all its original amounts. Material retained on tools and incomplete drying also affect measured recovery.

Use mass records to evaluate the plan. An illustrative dry starting mixture has 10 g gravel, 8 g sand and 2 g sugar, totaling 20 g. Suppose dry recovered portions are 9.8 g gravel, 7.6 g sand and 1.7 g sugar. Total recovery is 19.1 g, so 0.9 g is not in the recovered portions. Possible locations include material stuck to containers, spilled grains or sugar remaining in residual solution. The discrepancy is not evidence that the missing matter ceased to exist.

The diagram represents the full initial 20 g as recovered categories plus the 0.9 g unaccounted remainder. “Unaccounted” means not located by the current measurement record; it is not a fourth original ingredient. If recovered sand is still wet, its measured mass includes added water and can falsely suggest unusually high recovery. Drying, consistent boundaries and instrument precision matter as much as addition and subtraction.

Volume requires a separate argument. Pouring small dry beads into spaces between larger beads can give a combined bulk volume smaller than the sum of their separately measured bulk volumes. No bead disappears; the original bulk measurements included spaces that become occupied. This is a useful packing analogy, but molecules in liquids have interactions and arrangements that are more complex than loose beads. Do not treat it as a literal picture of every dissolved substance.

Water and dissolved sugar likewise need not produce a final volume equal to separately read initial volumes. Conservation of mass does not require conservation of volume. Liquid volumes do not always add up exactly. Rubbing alcohol and water is a common classroom example: if the mixture is allowed to return to the starting temperature before its volume is read (mixing can change its temperature), the mixed volume can come out a little less than the two volumes added together. If nothing spills or evaporates, the mass still equals the two masses added together. Temperature changes can also change volume without changing the atom inventory. A closed, room-temperature dissolution test can support mass conservation while demonstrating that disappearance from sight is not disappearance of matter.

For that test, place a small separate cup of sugar and a water cup inside an appropriate closed transparent container selected by the teacher. Weigh the whole closed setup, mix the contents internally without opening the boundary, and weigh it again. Keep all containers and lids within the account. Use no gas-producing reaction or heated sealed apparatus. Report resolution and any leakage or handling problem instead of replacing imperfect observations with expected results.

Section 2 · ModelWork through the examples

Worked recovery: 9.8 + 7.6 + 1.7 = 19.1 g dry recovery. Relative to the 20 g starting dry mixture, the recovery fraction is 19.1/20 = 0.955, or 95.5%. The unaccounted 0.9 g is 4.5%. Added water is a separate input and must not be counted as recovered original dry material.

Worked process choice: A student proposes filtering sugar water to recover solid sugar. An ordinary filter does not retain individual dissolved sugar molecules. Evaporation can leave sugar behind but releases water to air; collecting both components requires an additional vapor-collection and condensation arrangement.

Section 3 · DoPractice, demonstrate, and explain

Supported investigation: Compare teacher-prepared sugar water and sand water using settling and ordinary filtration. Record observations, test the filter with a known visible-particle sample and explain why clear liquid need not be pure. Do not taste samples.

Independent separation design: Use an adult-approved unknown mixture of safe supplied materials and available tools. Identify relevant properties, write and test a sequence, preserve all collected fractions and report dry mass recovery with uncertainty. Explain the fate of any added water and unaccounted material. Include a separate bead-packing demonstration of nonadditive bulk volumes and identify its limitation as a molecular analogy.

Section 4 · Check6-question lesson practice test

An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.

Problem 1

Does sugar disappear as matter when it dissolves?

Show worked solution

No. Sugar molecules disperse among water molecules while retaining their identities; the dissolved material still contributes mass.

Problem 2

Why can a paper filter separate sand from water but not dissolved sugar from water?

Show worked solution

Its openings can retain larger sand particles, while dissolved sugar passes through with the liquid.

Problem 3

How does a typical suspension differ from a solution?

Show worked solution

Its larger dispersed particles can settle and often be filtered; a solution contains dissolved particles distributed at a much smaller scale.

Problem 4

Find the unaccounted dry mass when 19.1 g is recovered from 20 g.

Show worked solution

0.9 g. It may remain on tools, in residual solution or elsewhere outside the recovered fractions; the separation did not destroy matter, so investigate unrecovered material and measurement error.

Problem 5

Why can wet sand produce a misleading recovery mass?

Show worked solution

The balance includes retained added water as well as sand, so it is not a comparable dry-material measurement.

Problem 6

Does conserved mass require initial bulk volumes to add exactly?

Show worked solution

No. Packing, spacing, interactions and temperature can change occupied volume while all matter remains accounted for.