Grade 7 · MathematicsAbout 150 minutes
MathematicsGrade 7About 150 minutes

Choose equivalent forms that reveal a quantity relationship

Multiple sessions for representations, property-based reasoning, fluent practice and independent contextual problems.

Ohio learning standards this draft targets

math-2017:7.EE.2

Read the standard text

math-2017:7.EE.2 In a problem context, understand that rewriting an expression in an equivalent form can reveal and explain properties of the quantities represented by the expression and can reveal how those quantities are related. For example, a discount of 15% (represented by p − 0.15p) is equivalent to (1 − 0.15)p, which is equivalent to 0.85p or finding 85% of the original price.

Provisional targets. Clause-by-clause educational review is still pending.

Study these connected lessons together: Add, subtract, expand and factor linear expressions.

Section 1 · LearnLearn the idea
Original price p contains twenty equal five-percent parts. Three parts represent the 15% markdown; seventeen represent the retained 85%. Thus p − 0.15p = 0.85p, and both portions belong to the original whole.Original price p contains twenty equal five-percent parts. Three parts represent the 15% markdown; seventeen represent the retained 85%. Thus p − 0.15p = 0.85p, and both portions belong to the original whole.One original price · twenty equal partsEach part is 5% of pAll twenty parts = 100% of pRemoved: 3/20 = 15%Retained: 17/20 = 85%p − 0.15p = 0.85p
Original price p contains twenty equal five-percent parts. Three parts represent the 15% markdown; seventeen represent the retained 85%. Thus p − 0.15p = 0.85p, and both portions belong to the original whole.

Learning goal: Rewrite an expression in an equivalent form and explain what each form reveals about a situation. Use the context to interpret coefficients, grouped quantities and the reference whole.

Equivalent expressions can display different features of the same quantity. A form that is convenient for calculating may hide the sequence described in a story; another may make a relationship visible. The point of rewriting is not only to shorten symbols. Explain what a reader can understand more directly from the new form.

Let p be a positive original price in a hypothetical 15% markdown model. The expression p − 0.15p shows the original amount with a discount subtracted. Factoring p gives (1 − 0.15)p, which simplifies to 0.85p. This form shows immediately that the customer pays 85% of the original price. The 0.15 and 0.85 refer to complementary shares of the same original whole.

The rewritten form does not say the discount is 85%; that is the fraction retained. A bar with twenty equal parts can show three parts removed, since 3/20 = 15%, and seventeen retained, since 17/20 = 85%. Every outlined part belongs to the original price. The removed portion and retained portion together reconstruct the whole.

A price increase has a similar structure. p + 0.08p = 1.08p means 100% of p plus another 8% of p. The coefficient 1.08 describes the final amount as a multiple of the original, while 0.08 describes the increase alone. If an added fee has a different base or is fixed, keep that term separate rather than folding it into a percentage without justification.

For a rectangle with length l and width w, the perimeter can be written l + w + l + w, 2l + 2w or 2(l + w). The first form displays all four sides; the second displays the two equal pairs; the third displays twice the sum of adjacent side lengths. All represent the same boundary length for the rectangle. They do not represent area, which uses a different relationship.

If a rectangular garden has length x + 3 and width x, its perimeter is 2(x + 3) + 2x = 4x + 6. The expanded form shows four copies of the base length x plus six additional units from the two longer sides. Factoring gives 2(2x + 3), which emphasizes one length-width pair doubled. The context explains why the constant six appears, rather than treating it as an unexplained byproduct of symbols.

A grouping can reveal a repeated package. Suppose each model kit contains two pencils and three cards, with pencil cost a and card cost b. Four identical kits cost 4(2a + 3b), assuming no other charges. Expanding gives 8a + 12b, showing the total quantities of each component. The first form helps reason per kit; the second helps plan the complete supply order.

A different expression can reveal savings. If a normal total for n entries is 5n but a group receives a fixed ten-unit reduction, 5n − 10 = 5(n − 2). Algebraically, the cost equals the price of n minus two full-price entries. Whether the organizer actually grants two free entries is a contextual interpretation, not something the algebra proves about the policy's wording. The original rule says a fixed reduction; the equivalent form reveals the same numerical effect where the model applies.

Domain restrictions remain important. A price p should be nonnegative in the simple purchase context; a rectangle's side lengths should be positive; a kit count may be a whole number. Equivalent expressions agree for their allowed inputs, but a negative cost produced by extending a discount formula to too few entries may fall outside the policy's intended domain. State those conditions when explaining the form.

To compare two forms, identify the same quantity, expand or factor with valid properties, then interpret the pieces. Do not claim two expressions are equivalent merely because they match at one input. For example, x + 2 and 2x match at x = 2 but differ elsewhere. A contextual explanation should be supported by a general algebraic relationship as well as a numerical check.

Section 2 · ModelWork through the examples

Worked price: At p = 80, p − 0.15p = 80 − 12 = 68. The form 0.85p gives 0.85 × 80 = 68. The first highlights the twelve-unit markdown; the second highlights the retained 85%. Both use eighty as the reference whole.

Worked perimeter: With x = 5, the garden is eight by five, so perimeter is 8 + 5 + 8 + 5 = 26. The form 4x + 6 gives twenty plus six, and 2(2x + 3) gives twice thirteen. Each form reveals a different grouping of the same four boundary lengths.

Worked interpretation limit: 5n − 10 = 5(n − 2) is useful for comparing the final amount with a full-price entry total. It does not prove that exactly two named people are admitted for free or that the rule applies when n is one. State the original pricing rule and its domain before interpreting the equivalent form.

Section 3 · DoPractice, demonstrate, and explain

Form-selection task: For the markdown, rectangle and kit examples, write two equivalent forms and a sentence explaining the feature each reveals. Choose which form is more helpful for a particular question: calculating a final price, finding component counts or recognizing a repeated boundary pair.

Independent performance: Create three contextual expressions with rational coefficients, including a percent change and a geometric or material-use example. Rewrite each into an equivalent form and justify the algebra. Explain what the new coefficient or group means, identify the reference whole when relevant, and state any domain restrictions. A partner checks whether the interpretation says only what the expression and situation support.

Section 4 · Check6-question lesson practice test

An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.

Problem 1

What does 0.85p reveal that p − 0.15p expresses less directly?

Show worked solution

The final amount is 85% of the original price p.

Problem 2

Why do the retained and removed portions add to p?

Show worked solution

They are complementary shares of the same original whole: 85% plus 15% equals 100%.

Problem 3

What does 2(l + w) reveal about a rectangle’s perimeter?

Show worked solution

The sum of one adjacent length-width pair is doubled to account for all four sides.

Problem 4

What does expanding 4(2a + 3b) to 8a + 12b reveal?

Show worked solution

The total order contains eight pencil-cost units and twelve card-cost units across the four identical kits.

Problem 5

Why does 5(n − 2) not necessarily prove two named people enter free?

Show worked solution

It shows an equivalent numerical effect of the fixed reduction, not the exact policy mechanism or who receives it.

Problem 6

What is needed beyond one matching numerical example?

Show worked solution

A valid algebraic transformation establishing equivalence and a contextual interpretation within the allowed domain.