Problem 1
Evaluate 3⁴.
Show worked solution
81, from four factors of three.
math-2017:6.EE.1math-2017:6.EE.2math-2017:6.EE.2c
math-2017:6.EE.1 Write and evaluate numerical expressions involving whole number exponents.
math-2017:6.EE.2 Write, read, and evaluate expressions in which letters stand for numbers.
math-2017:6.EE.2c Evaluate expressions at specific values of their variables. Include expressions that arise from formulas used in real-world problems. Perform arithmetic operations, including those involving whole number exponents, using the algebraic order of operations when there are no parentheses to specify a particular order. For example, use the formulas V = s³ and A = 6s² to find the volume and surface area of a cube with sides of length s = 1/2.
Study these connected lessons together: Write expressions, identify their parts and substitute values, Generate and justify equivalent expressions.
Learning goal: Write repeated multiplication with whole-number exponents and evaluate numerical expressions according to grouping and operation order. Use powers in a formula without confusing an exponent with a multiplier.
In 3⁴, three is the base and four is the exponent. The expression means four factors of three: 3 × 3 × 3 × 3 = 81. It does not mean 3 × 4, which is twelve. The exponent counts repeated factors, not repeated additions. For a positive whole-number exponent, writing the expanded product can clarify an unfamiliar power.
A square with side length four units has area 4² = 4 × 4 = 16 square units. A cube with side length two units has volume 2³ = 2 × 2 × 2 = 8 cubic units. The words squared and cubed connect powers with these geometric examples, but exponents can also describe repeated multiplication outside geometry.
The diagram shows sixteen equal unit squares in a four-by-four array and three equal factors in 2 × 2 × 2. The array's entire area is sixteen square units; the four squares along one edge give a length of four units. Confusing an edge count with an area count would make 4² look like four rather than sixteen.
The order of operations determines how a conventional expression is read. Evaluate grouped expressions first, then powers, then multiplication and division at the same priority from left to right, then addition and subtraction at the same priority from left to right. An acronym should not be interpreted as saying multiplication always precedes division or addition always precedes subtraction.
For 5 + 2³ × 4, evaluate 2³ = 8, then 8 × 4 = 32, then add five to get thirty-seven. For (5 + 2)³ × 4, the parentheses instead make seven the base of the cube: 7³ × 4 = 343 × 4 = 1,372. Grouping changes the mathematical structure, so it can change the result dramatically.
Equal-priority operations follow their written order. In 24 ÷ 6 × 2, first divide twenty-four by six to get four, then multiply by two to get eight. Treating 6 × 2 as a denominator would require parentheses: 24 ÷ (6 × 2) = 2. Similarly, 10 − 3 + 2 = 9, while 10 − (3 + 2) = 5.
A whole-number exponent can be one or zero. For any base a, a¹ = a. For a nonzero base, a⁰ = 1. A pattern explains the zero exponent: 3³ = 27, 3² = 9 and 3¹ = 3 decrease by dividing by three, so continuing one step gives 3⁰ = 1. Do not apply this explanation to 0⁰, which requires a separate convention and is not used in this lesson.
Fractional side lengths can appear in formulas even when the exponent is a whole number. For a cube with side s = 1/2 meter, V = s³ gives (1/2)³ = 1/8 cubic meter. The surface-area formula A = 6s² gives 6 × (1/2)² = 6 × 1/4 = 3/2 square meters. The exponent acts on the side length, while six multiplies the area of one face.
Write a substitution before calculating. A = 6(1/2)² makes clear that the entire one-half side length is squared. Computing (6 × 1/2)² would square a different quantity and produce nine instead of one and one half. Parentheses and unit labels protect the intended structure.
Expressions with letters and powers can also be written from words and read in parts. “The cube of s” is written s³, and “six times the square of s” is 6s². The expression 6s² is a product of two factors, the coefficient 6 and the power s²; within s², s is the base and 2 is the exponent. In 5 + 2³ × 4, the whole expression is a sum of two terms, 5 and 2³ × 4, and the second term is itself a product. Naming the parts shows which operation is completed last.
Worked evaluation: 30 − 2² × 3 = 30 − 4 × 3 = 30 − 12 = 18. Subtracting thirty minus two first would ignore the power and product structure.
Worked correction: “4³ is 4 + 4 + 4.” That sum is 3 × 4 = 12. The power 4³ is 4 × 4 × 4 = 64. State whether the notation counts equal addends or equal factors before computing.
Guided structure work: Expand several powers into factors and rewrite repeated products as powers. Compare pairs of expressions that differ only by parentheses. Explain which operation is completed first and why.
Independent performance: Evaluate expressions involving powers and mixed operations, including equal-priority multiplication/division and addition/subtraction. Use a fractional side length in both cube formulas, label square and cubic units and explain the role of each exponent. Create an incorrect evaluation based on confusing factors with addends, then correct it with a model or expanded product.
An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.
Evaluate 3⁴.
81, from four factors of three.
Evaluate 5 + 2³ × 4.
37: exponent first, then multiplication, then addition.
Evaluate 24 ÷ 6 × 2.
8, working division and multiplication left to right.
Evaluate 30 − 2² × 3.
18, since 2² × 3 = 12.
Find cube volume when side length is one half meter.
1/8 cubic meter (0.125 cubic meter), from (1/2)³.
Find that cube’s surface area using A = 6s².
3/2 square meters (also written 1 1/2 or 1.5), from six faces each having area 1/4 square meter.
Write 5 × 5 × 5 as a power and evaluate it.
5³ = 125; the exponent 3 counts three factors of five, so the value is not 5 × 3 = 15.
Evaluate 2 × 3² + 4² ÷ 8.
20: the powers come first, giving 2 × 9 + 16 ÷ 8, then multiplication and division give 18 + 2.