Grade 6 · MathematicsAbout 120 minutes
MathematicsGrade 6About 120 minutes

Find greatest common factors and least common multiples

Connect each written step to place value or factor structure, then observe accurate independent computation across varied examples.

Ohio learning standards this draft targets

math-2017:6.NS.4

Read the standard text

math-2017:6.NS.4 Find the greatest common factor of two whole numbers less than or equal to 100 and the least common multiple of two whole numbers less than or equal to 12. Use the distributive property to express a sum of two whole numbers 1-100 with a common factor as a multiple of a sum of two whole numbers with no common factor. For example, express 36 + 8 as 4 (9 + 2).

Provisional targets. Clause-by-clause educational review is still pending.

Section 1 · LearnLearn the idea
Six identical packs each hold three blue and five gold cards, using all eighteen blue and thirty gold cards. The grouping shows 18 + 30 = 6(3 + 5) = 48.Six identical packs each hold three blue and five gold cards, using all eighteen blue and thirty gold cards. The grouping shows 18 + 30 = 6(3 + 5) = 48.Six equal packs · every card includedPack 1Pack 2Pack 3Pack 4Pack 5Pack 618 blue + 30 gold = 6(3 + 5) = 48 cards
Six identical packs each hold three blue and five gold cards, using all eighteen blue and thirty gold cards. The grouping shows 18 + 30 = 6(3 + 5) = 48.

Learning goal: Find the greatest common factor of two whole numbers at most one hundred and the least common multiple of two positive whole numbers at most twelve. Use factor structure and the distributive property to rewrite a sum as a common factor times a sum whose terms share no factor greater than one.

A factor divides a whole number without a remainder. The positive factors of eighteen are 1, 2, 3, 6, 9 and 18. Those of thirty are 1, 2, 3, 5, 6, 10, 15 and 30. Their common factors are 1, 2, 3 and 6, so the greatest common factor, or GCF, is six. Greatest means the largest shared factor, not the larger original number.

Suppose eighteen blue cards and thirty gold cards are distributed into the greatest possible number of identical packs with no cards left. Each pack must contain the same number of blue cards and the same number of gold cards. The pack count must divide both eighteen and thirty. Six packs work, with three blue and five gold in each. Nine packs fail because thirty cannot be divided into nine equal whole-card groups.

The diagram shows six actual packs, each containing three blue and five gold cards. Counting all packs recovers eighteen blue and thirty gold. The common factor six counts packs; the numbers three and five count cards of each color per pack. The total card count is forty-eight.

The distributive property expresses that grouping: 18 + 30 = 6 × 3 + 6 × 5 = 6(3 + 5). Three and five share no positive common factor greater than one. Factoring out only two gives 2(9 + 15), which is equivalent but leaves another common factor inside. Factoring out the GCF leaves inner terms with no common factor greater than one, which is the form the standard asks for.

A multiple is the result of multiplying a number by a whole number. Positive multiples of six include 6, 12, 18, 24 and 30. Positive multiples of eight include 8, 16, 24 and 32. The least common multiple, or LCM, is twenty-four, the smallest positive value in both lists. Zero is a multiple of both, but it is not the least positive common multiple sought here.

If two classroom signals begin together and repeat every six minutes and eight minutes, they next occur together after twenty-four minutes, assuming both schedules continue exactly. One signal occurs at 6, 12, 18 and 24 minutes; the other at 8, 16 and 24. The LCM answers the shared-timing question. The GCF, two, answers a different divisibility question and is not the next meeting time.

Prime factors provide another method. Eighteen is 2 × 3 × 3; thirty is 2 × 3 × 5. Their shared prime factors give 2 × 3 = 6 for the GCF. For six and eight, the factorizations are 2 × 3 and 2 × 2 × 2. A common multiple must include enough factors for each number, so the LCM is 2 × 2 × 2 × 3 = 24.

Multiplying the two numbers always gives a common multiple, but it may not give the least one. Six times eight is forty-eight, a shared multiple larger than twenty-four. Likewise, one is always a positive common factor, but it may not be the greatest. The words least and greatest require comparing eligible values or using factor structure that shows no greater common factor, or no smaller common multiple, exists.

When one number divides the other, the relationship is especially clear. For four and twelve, the GCF is four and the LCM is twelve. For relatively prime positive numbers such as five and eight, the GCF is one and the LCM is forty. Relatively prime describes the pair's shared factors, not a claim that both numbers individually are prime.

Section 2 · ModelWork through the examples

Worked distribution: For 36 + 84, the GCF is twelve. Write 12(3 + 7) = 120. The inner terms three and seven have no common factor greater than one. The equality can be checked by distributing twelve back to each term.

Worked choice of operation: Identical packs with no leftover objects require a common divisor of the two counts. Repeating schedules meeting again require a common multiple of the intervals. Decide what the unknown counts before choosing GCF or LCM.

Section 3 · DoPractice, demonstrate, and explain

Guided factor work: List factors of eighteen and thirty, then verify the six-pack model. List positive multiples of six and eight until the first shared value appears. Connect both lists with prime-factor reasoning and explain the different roles of the answers.

Independent performance: Find GCFs for pairs at most one hundred, LCMs for pairs at most twelve, and rewrite two sums using the GCF and distribution. Include one pair where one number divides the other and one relatively prime pair. Create a packing problem and a schedule problem, identify the required structure and justify why your answer is greatest or least as requested.

Section 4 · Check8-question lesson practice test

An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.

Problem 1

Find the GCF of eighteen and thirty.

Show worked solution

Six, the largest value dividing both without a remainder.

Problem 2

Eighteen blue cards and thirty gold cards are split into the greatest possible number of identical packs with none left over. How many packs are there, and what does each hold?

Show worked solution

Six packs, each containing three blue and five gold cards.

Problem 3

Rewrite 18 + 30 with its greatest common factor.

Show worked solution

6(3 + 5); the inner terms share no factor greater than one. Writing the inner terms in the other order, 6(5 + 3), is equally correct.

Problem 4

Find the LCM of six and eight.

Show worked solution

Twenty-four, the first positive multiple appearing in both sequences.

Problem 5

Rewrite 36 + 84 using the GCF.

Show worked solution

12(3 + 7), with GCF twelve and total 120.

Problem 6

Why is forty-eight not the LCM of six and eight?

Show worked solution

It is a common multiple, but twenty-four is a smaller positive common multiple.

Problem 7

Find the greatest common factor of 45 and 63 and use it to rewrite 45 + 63.

Show worked solution

The GCF is 9, so 45 + 63 = 9(5 + 7) = 108; 5 and 7 share no factor greater than one.

Problem 8

In a hypothetical game, one light flashes every 9 seconds and another every 12 seconds. They flash together now. After how many seconds do they next flash together?

Show worked solution

36 seconds, the least common multiple of 9 and 12: the multiples 9, 18, 27, 36 and 12, 24, 36 first agree at 36. The product 108 is a common multiple but not the least.