Grade 4 · MathematicsAbout 90 minutes
MathematicsGrade 4About 90 minutes

Distinguish times as many from more than

Suggested multi-session teaching plan.

Ohio learning standards this draft targets

math-2017:4.OA.1math-2017:4.OA.2

Read the standard text

math-2017:4.OA.1 Interpret a multiplication equation as a comparison, e.g., interpret 35 = 5 × 7 as a statement that 35 is 5 times as many as 7 and 7 times as many as 5. Represent verbal statements of multiplicative comparisons as multiplication equations.

math-2017:4.OA.2 Multiply or divide to solve word problems involving multiplicative comparison, e.g., by using drawings and equations with a symbol for the unknown number to represent the problem, distinguishing multiplicative comparison from additive comparison. See Table 2, page 95. Drawings need not show details, but should show the mathematics in the problem. (This applies wherever drawings are mentioned in the Standards.)

Provisional targets. Clause-by-clause educational review is still pending.

Section 1 · LearnLearn the idea
Lena’s 7 tiles form one reference unit. Omar’s 35 tiles form five equal units of 7: five times as many, or 28 more tiles.Lena’s 7 tiles form one reference unit. Omar’s 35 tiles form five equal units of 7: five times as many, or 28 more tiles.Compare using the same seven-tile unitLena7Omar7777728 more tiles35 = 5 × 7 and 35 − 7 = 28
Lena’s 7 tiles form one reference unit. Omar’s 35 tiles form five equal units of 7: five times as many, or 28 more tiles.

Learning goal: Interpret multiplication as a comparison, distinguish it from an additive comparison and solve for different unknown quantities. Comparisons describe a relationship between two amounts. The words times as many and more than name different relationships even when the same two numbers appear in the problem.

Lena has seven model tiles and Omar has thirty-five. Omar has five times as many tiles as Lena because five groups of seven make thirty-five. Write 35 = 5 × 7. The factor five is the multiplier in this comparison; seven is the reference amount, and thirty-five is the compared amount. A bar model uses one seven-tile unit for Lena and five equal seven-tile units for Omar.

The same pair also supports an additive comparison: Omar has twenty-eight more tiles than Lena, because 35 − 7 = 28. Five times as many does not mean five more. Adding five to seven gives twelve, a different amount. Draw both relationships when the language is confusing: repeated equal units for the multiplicative comparison and an extra-length difference for the additive comparison.

A multiplication equation can support more than one comparison. Thirty-five is five times as many as seven, and it is seven times as many as five. The product stays the same when factors change order, but the reference amount changes. In a particular story, identify which amount belongs to which person or object before interpreting the equation.

In a times-as-many comparison, when the compared amount is unknown, multiply the reference amount by the multiplier. A ribbon is three times as long as an eight-centimeter sample. Write r = 3 × 8, so the ribbon is twenty-four centimeters long. Three counts how many sample-length units fit the ribbon. It is not a length of three centimeters added to the sample. A story saying the ribbon is three centimeters longer than the sample would be a more-than comparison, and that ribbon would be 8 + 3 = 11 centimeters long.

When the multiplier is unknown, divide the compared amount by the reference amount. A twenty-four-centimeter ribbon is how many times as long as an eight-centimeter sample? Write 24 = m × 8, then m = 24 ÷ 8 = 3. The answer is three times, not three centimeters. The quotient's unit depends on what is unknown.

In a times-as-many comparison, when the reference amount is unknown, division finds that amount. A ribbon is twenty-four centimeters long and is three times as long as a sample. Write 24 = 3 × s, so s = 8 centimeters. This time the answer is a length. The two division questions use the same quantities but ask for different meanings.

Always check the original comparison. If a result says the shorter sample is seventy-two centimeters long while the ribbon is twenty-four, it contradicts the statement that the ribbon is three times as long. A numerical operation is useful only when it represents the relationship correctly.

Section 2 · ModelWork through the examples

Worked comparison: A small collection has six shells. A large collection has four times as many. Find 4 × 6 = 24 shells. The additive difference is 24 − 6 = 18 shells. Four is the multiplier; eighteen is how many more. These answers should not be exchanged.

Worked unknown reference: A team collects forty-eight cans, six times as many as another team. Let c be the other team's collection: 48 = 6 × c. Divide to get c = 8 cans, then check that six groups of eight make forty-eight.

Section 3 · DoPractice, demonstrate, and explain

Guided practice: Use matching bar units to model a known reference, a missing multiplier and a missing reference. Pair each multiplicative question with an additive comparison about the same amounts. Explain the counted or measured unit of every answer.

Independent evidence: Write equations and labeled drawings for unfamiliar comparison stories, including an unknown in each role. Explain why a five-more strategy does not solve a five-times-as-many problem. If a learner chooses an operation from a keyword alone, return to the reference amount and the equal units shown in the model. Drawings need not show details such as every tile or the color of a ribbon, but they should show the mathematics in the problem: which amount is the reference unit, how many equal units the compared amount contains, and which quantity is unknown.

Section 4 · Check7-question lesson practice test

An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.

Problem 1

Omar has 35 tiles and Lena has 7. How many times as many does Omar have?

Show worked solution

Five times as many, since 35 ÷ 7 = 5.

Problem 2

How many more tiles does Omar have?

Show worked solution

28 more tiles: 35 − 7 = 28.

Problem 3

A rope is four times as long as a nine-meter rope. Find its length.

Show worked solution

36 meters: 4 × 9 = 36. Four counts equal nine-meter units; it is not four meters added on.

Problem 4

A 42-centimeter ribbon is six times as long as a sample. Find the length of the sample.

Show worked solution

7 centimeters: 42 = 6 × s, so s = 42 ÷ 6 = 7. Check: six lengths of 7 centimeters make 42 centimeters.

Problem 5

A 56-page book has how many times as many pages as an 8-page booklet?

Show worked solution

Seven times as many, since 56 ÷ 8 = 7. This quotient is a multiplier, not a number of pages.

Problem 6

Why does adding five to seven not represent five times as many as seven?

Show worked solution

It gives twelve. Five times as many requires five equal groups of seven, totaling thirty-five.

Problem 7

Mia has 9 stickers. Jon has 3 times as many stickers as Mia, and Kai has 3 more stickers than Mia. How many stickers does each have, and which kind of comparison is each?

Show worked solution

Jon has 27 stickers, because 3 × 9 = 27; that is a times-as-many comparison. Kai has 12 stickers, because 9 + 3 = 12; that is a more-than comparison. The same number 3 gives different answers because the two relationships differ.