Grade 3 · MathematicsAbout 90 minutes
MathematicsGrade 3About 90 minutes

Connect equal groups, multiplication and division

Suggested multi-session teaching plan.

Ohio learning standards this draft targets

math-2017:3.OA.1math-2017:3.OA.2math-2017:3.OA.3math-2017:3.OA.4math-2017:3.OA.6

Read the standard text

math-2017:3.OA.1 Interpret products of whole numbers, e.g., interpret 5 x 7 as the total number of objects in 5 groups of 7 objects each. (Note: These standards are written with the convention that a x b means a groups of b objects each; however, because of the commutative property, students may also interpret 5 x 7 as the total number of objects in 7 groups of 5 objects each).

math-2017:3.OA.2 Interpret whole number quotients of whole numbers, e.g., interpret 56 ÷ 8 as the number of objects in each share when 56 objects are partitioned equally into 8 shares, or as a number of shares when 56 objects are partitioned into equal shares of 8 objects each. For example, describe a context in which a number of shares or a number of groups can be expressed as 56 ÷ 8.

math-2017:3.OA.3 Use multiplication and division within 100 to solve word problems in situations involving equal groups, arrays, and measurement quantities, e.g., by using drawings and equations with a symbol for the unknown number to represent the problem. See Table 2, page 95. Drawings need not show details, but should show the mathematics in the problem. (This applies wherever drawings are mentioned in the Standards.)

math-2017:3.OA.4 Determine the unknown whole number in a multiplication or division equation relating three whole numbers. For example, determine the unknown number that makes the equation true in each of the equations 8 × □ = 48; 5 = □ ÷ 3; 6 × 6 = □ .

math-2017:3.OA.6 Understand division as an unknown-factor problem. For example, find 32 ÷ 8 by finding the number that makes 32 when multiplied by 8.

Provisional targets. Clause-by-clause educational review is still pending.

Section 1 · LearnLearn the idea
Four trays each hold six seedlings: 4 × 6 = 24. Sharing 24 among 4 trays gives 6 per tray; grouping 24 in sixes gives 4 trays.Four trays each hold six seedlings: 4 × 6 = 24. Sharing 24 among 4 trays gives 6 per tray; grouping 24 in sixes gives 4 trays.4 equal trays · 6 seedlings per tray12346 + 6 + 6 + 6 = 4 × 6 = 24
Four trays each hold six seedlings: 4 × 6 = 24. Sharing 24 among 4 trays gives 6 per tray; grouping 24 in sixes gives 4 trays.

Learning goal: Represent equal groups and explain what each number means before calculating. A multiplication expression describes a number of groups and an equal amount in every group. Four trays with six seedlings on each tray contain 4 × 6 = 24 seedlings. Here the first factor counts trays and the second counts seedlings per tray. The product counts all seedlings.

An array arranges objects in equal rows and columns. Our picture has four rows of six seedlings. Count every row once: 6 + 6 + 6 + 6 = 24. A sketch can use dots instead of realistic plants. The arrangement must preserve the mathematical information: four equal groups, six in each, and twenty-four altogether. Three trays of six and one tray of five would not represent 4 × 6.

Division uses a known total to find a missing group quantity. In a sharing problem, twenty-four seedlings are shared equally among four trays. The number of trays is known; the size of each share is unknown. Write 24 ÷ 4 = □ seedlings per tray. Giving one seedling to each tray repeatedly produces six on every tray. Check 4 × 6 = 24.

In a grouping problem, twenty-four seedlings are packed six per tray. The size of each group is known; the number of trays is unknown. Write 24 ÷ 6 = □ trays. Circle groups of six until all twenty-four are used. There are four groups. Both stories involve the same total, but their answers count different things. Always name the unit of an answer.

Division can therefore be understood as a missing-factor problem. To solve 32 ÷ 8, ask what number multiplied by eight makes thirty-two. Four does, because 4 × 8 = 32. You may build equal groups, skip-count or use a known fact to find the missing factor. The multiplication equation checks the division result.

The box can occur anywhere in an equation. In 8 × □ = 48, the missing factor is six. In 5 = □ ÷ 3, five is the number in each share when the unknown total is divided into three equal shares. The total is fifteen, since 15 ÷ 3 = 5. The unknown can also be the number you divide by. Twenty-four seedlings are placed on some trays, the same number on each, and every tray ends up with six. The unknown is the number of trays: 24 ÷ □ = 6. Think of the related multiplication, □ × 6 = 24. Four works, because 4 × 6 = 24, so there are four trays. Check by putting four in the box: 24 ÷ 4 = 6 is true. The equals sign means both sides have the same value; it does not mean that an answer must appear on the right.

Equal-group reasoning also applies to measured lengths. A ribbon is twenty-four centimeters long. Cutting pieces six centimeters long, with no waste in this mathematical model, makes four pieces. The equation 24 ÷ 6 = 4 counts pieces, not centimeters per piece. Draw a twenty-four-centimeter bar partitioned into four six-centimeter lengths to show the relationship.

Section 2 · ModelWork through the examples

Worked example: Five bags each hold seven marbles. Draw five circles with seven marks in every circle, or five equal sections labeled seven. Write 5 × 7 = m, so m = 35 marbles. Reverse the question: thirty-five marbles are shared among five bags. Then 35 ÷ 5 = 7 marbles per bag. If each bag must hold seven, 35 ÷ 7 = 5 bags.

Check an error: A learner solves □ ÷ 3 = 5 with eight because three plus five is eight. Substitute eight into the original relationship: eight cannot make three whole-number shares of five. Fifteen can. Checking the original equation reveals the error rather than merely giving a different answer.

Section 3 · DoPractice, demonstrate, and explain

Practice with objects: Build two equal-group arrangements with totals below one hundred. For each, tell a multiplication story, a sharing story and a grouping story. Label the units and place the unknown in different positions. Then solve a new ribbon-length problem without copying the seedling numbers.

Independent evidence: Make a drawing and equation for an unfamiliar array problem and explain two different division interpretations. A correct numeral without the meaning of the quotient is incomplete evidence. If groups are unequal, rebuild them before calculating. These tasks establish the relationship; later practice develops efficient fact recall.

Section 4 · Check8-question lesson practice test

An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.

Problem 1

Nine boxes hold four balls each. How many balls?

Show worked solution

36 balls: 9 × 4 = 36. The factors count boxes and balls per box.

Problem 2

Share 36 balls equally among nine boxes. What does the quotient count?

Show worked solution

36 ÷ 9 = 4 balls per box. It counts the size of each share.

Problem 3

Pack 36 balls four per box. What does the quotient count?

Show worked solution

36 ÷ 4 = 9 boxes. It counts the boxes: the number of groups of four balls.

Problem 4

Solve 7 × □ = 56 and check.

Show worked solution

8; 7 × 8 = 56.

Problem 5

Solve 7 = □ ÷ 3. Explain why adding 7 and 3 does not work.

Show worked solution

21, because 21 ÷ 3 = 7. Ten would not make three shares of seven.

Problem 6

A 28-centimeter strip is cut into 7-centimeter pieces without waste. How many pieces?

Show worked solution

4 pieces, since 28 ÷ 7 = 4. A model should show four equal lengths of seven.

Problem 7

Solve 42 ÷ □ = 7 by thinking of a missing factor, then check by putting your answer in the box.

Show worked solution

6. The related multiplication is □ × 7 = 42, and 6 × 7 = 42. Check: 42 ÷ 6 = 7 is true.

Problem 8

A garden bed has 6 rows of 8 plants. Write an equation with a letter for the total and solve it.

Show worked solution

6 × 8 = p, so p = 48 plants. The array has six equal rows of eight.