Grades 11–12 · English language artsAbout 150 minutes
English language artsGrades 11–12About 150 minutes
Cite evidence from a technical text while attending to its distinctions and gaps, summarize its central conclusions in simpler but accurate terms, and follow a complex pendulum procedure and analyze the results
Several sessions: close reading of the original technical text, a supervised pendulum measurement, modeled analysis, independent practice and a written response.
ela-2017:RST.11-12.1 Cite specific textual evidence to support analysis of science and technical texts, attending to important distinctions the author makes and to any gaps or inconsistencies in the account.
ela-2017:RST.11-12.2 Analyze content-area-specific text development.
ela-2017:RST.11-12.2a Determine the central ideas or conclusions of a text.
ela-2017:RST.11-12.2b Provide an objective summary of the central ideas of a text, paraphrasing complex concepts, processes, or information by presenting them in simpler but still accurate terms.
ela-2017:RST.11-12.3 Follow precisely a complex multistep procedure when carrying out experiments, taking measurements, or performing technical tasks; analyze the specific results based on explanations in the text.
Provisional targets. Clause-by-clause educational review is still pending.
📘Section 1 · LearnLearn the idea
Hypothetical class results: T squared = 1.209, 2.013, 2.816 and 3.623 square seconds at lengths 0.300, 0.500, 0.700 and 0.900 m. The line drawn through the first and last points has slope 4.023 square seconds per meter and meets the vertical axis at 0.002 square seconds, almost exactly at the origin as the model predicts, so g = 39.478 / 4.023 = 9.81 m/s squared. Valid for amplitudes of 10 degrees or less.
Learning goal: Cite specific textual evidence to support analysis of science and technical texts, attending to important distinctions the author makes and to any gaps or inconsistencies in the account; determine the central ideas or conclusions of a text and provide an objective summary that paraphrases complex concepts, processes or information in simpler but still accurate terms; and follow precisely a complex multistep procedure when carrying out an experiment and taking measurements, then analyze the specific results based on explanations in the text.
Original technical text — "Measuring g with a Simple Pendulum" (a lab handout written for this lesson).
Background. A simple pendulum is a small, dense bob hanging from a light string that does not stretch. When the bob is pulled aside and released, it swings back and forth. The time for one complete oscillation, from one side to the other and back to the same point moving in the same direction, is the period, T. For an ideal pendulum swinging through a small angle, T = 2π√(L/g), where L is the length from the pivot to the center of mass of the bob and g is the acceleration due to gravity. The period of a pendulum does not depend on how far it swings or on the mass of the bob. Squaring both sides gives T² = (4π²/g)L, so a graph of T² against L is a straight line through the origin with slope 4π²/g. Measuring the slope therefore measures g.
Procedure. (1) Clamp the stand to the bench with a C-clamp. Hang a bob of 100 g to 200 g from a string, and measure the string length with a meter stick to the nearest 0.001 m. (2) Pull the bob aside so that the string makes an angle of no more than 10° with the vertical, checked with a protractor held at the pivot, and release it without pushing. (3) Let the pendulum make two swings, then start the stopwatch as the bob passes the lowest point, and time 20 complete oscillations. (4) Do three trials. If the three times differ by more than 0.3 s, do a fourth trial and report all four. (5) If the bob moves in an ellipse instead of a plane, stop it and release again. (6) Repeat for lengths of about 0.300, 0.500, 0.700 and 0.900 m. (7) For each length, compute the mean time, T = mean time ÷ 20, and T². Plot T² against L and find the slope.
Safety. Keep the swing path clear and below head height; stand to the side, not in front, of the swinging bob; keep the clamp tight throughout.
Sample results (hypothetical class data). Mean times for 20 oscillations: 21.987 s at 0.300 m; 28.373 s at 0.500 m; 33.560 s at 0.700 m; 38.067 s at 0.900 m. The class obtained g = 9.81 m/s², which agrees closely with the accepted value near Earth's surface. Mass had no effect on the period.
Attending to the author's distinctions. Technical writers make distinctions on which everything depends, and a careful reader cites them. This text distinguishes a complete oscillation (there and back to the same point moving the same way) from a single swing (one side to the other). Timing swings instead of oscillations would halve every period and quadruple g's apparent size, since g = 4π²L/T². It also distinguishes the ideal pendulum (light string, point-like bob, small angle) from a real one. The formula is stated for the ideal case "swinging through a small angle," and that condition matters.
Finding gaps and inconsistencies. Now read critically. First, an inconsistency: the Background says L is measured "from the pivot to the center of mass of the bob," but procedure step 1 says to measure "the string length." These differ by roughly the bob's radius. Second, an overstatement: the Background says the period "does not depend on how far it swings," yet the formula is stated for small angles and step 2 limits the angle to 10°. Both cannot be exactly right. In fact, the period increases slightly with amplitude; for a 10° amplitude the ideal small-angle formula underestimates the period by about 0.2 percent, and at 20° by about 0.8 percent. The procedure is correct; the unconditional sentence is not. Third, a gap: the Sample results claim "mass had no effect," but the procedure uses one bob and gives no data with a second mass. The claim may be true for an ideal pendulum, but this text provides no evidence for it.
Central conclusions and an objective summary. Analyzing content-area-specific text development means tracing how a science or technical text builds toward its central conclusion in the way such texts typically develop: this handout moves from a model (Background, which states the formula and its conditions), to a method designed to test the model (Procedure), to a precaution (Safety), to results interpreted through the model (Sample results). Each part depends on the one before: the procedure makes sense only once the formula says what to measure. The central conclusion is that measuring how the period depends on length, and graphing T² against L, gives g from the slope. Paraphrasing complex concepts in simpler but still accurate terms is a skill with two failure modes: too technical (copying the formula without explaining it) and too simple (losing a condition). "A longer pendulum swings slower, so you can find gravity" is simpler but not accurate enough: it omits what is measured and how. A strong paraphrase: "For small swings, the square of the time for one back-and-forth swing is proportional to the pendulum's length. The constant of proportionality depends only on gravity, so plotting the squared period against length and measuring the line's steepness gives the strength of gravity."
Following a complex procedure precisely. Each step exists for a reason given or implied in the text. Timing 20 oscillations instead of one divides the reaction-time error of starting and stopping the watch by 20. Starting at the lowest point, where the bob moves fastest, makes the moment of passing easiest to judge. Letting it make two swings first allows any wobble from the release to die away. The 0.3 s rule catches a miscounted oscillation (a miscount by one adds about a whole period, more than 1 s here). The ellipse rule protects the assumption that the bob moves in a plane.
A fully worked model of the analysis. Period at 0.300 m: 21.987 ÷ 20 = 1.09935 s; T² = 1.209 s². At 0.900 m: 38.067 ÷ 20 = 1.90335 s; T² = 3.623 s². Slope between these points: (3.623 − 1.209) ÷ (0.900 − 0.300) = 2.414 ÷ 0.600 = 4.023 s²/m. Then g = 4π² ÷ slope = 39.478 ÷ 4.023 = 9.81 m/s². The handout's model shows why the slope method is robust: if every L had been measured to the string only, 0.010 m short for a bob of radius 1.0 cm, every point shifts left by the same amount, the slope is unchanged and g stays 9.81 m/s², provided the slope is taken between data points or from a best-fit line allowed its own intercept. The error shows up instead as a nonzero intercept; a line forced through the origin would absorb the offset into the slope and give a low g (about 9.66 m/s² with these data). But a single-point calculation with the short length, g = 4π² × 0.290 ÷ 1.209, gives 9.47 m/s², more than 3 percent low.
A misconception. Students often treat a close agreement with the accepted value as proof that every claim in the text is right. Agreement for g says nothing about the untested claim that mass has no effect.
✏️Section 2 · ModelWork through the examples
Worked citation of a gap: Claim: the handout's statement that mass has no effect is not supported by its own evidence. Evidence: step 1 says "Hang a bob of 100 g to 200 g," singular, and the sample results report only one set of times per length, then state "Mass had no effect on the period." Reasoning: to show no effect, the text would need periods for at least two masses at the same length and amplitude. The claim agrees with the ideal-pendulum model, but in this text it is asserted, not tested.
Worked summary in simpler but accurate terms: Complex text: "T² = (4π²/g)L, so a graph of T² against L is a straight line through the origin with slope 4π²/g." Too simple: "Bigger L means bigger T." (True but loses the square and the straight line.) Accurate paraphrase: "If you square each period and plot it against length, the points lie on a straight line starting at zero. How steep that line is depends only on gravity: the stronger gravity is, the less steep the line. So measuring the steepness measures gravity." Check: slope = 4π²/g decreases as g increases, so "stronger gravity, less steep" is accurate.
Worked analysis of results: Middle points: at 0.500 m, 28.373 ÷ 20 = 1.41865 s and T² = 2.013 s²; at 0.700 m, 33.560 ÷ 20 = 1.6780 s and T² = 2.816 s². Point-by-point g = 4π²L/T²: 39.478 × 0.500 ÷ 2.013 = 9.81 m/s²; 39.478 × 0.700 ÷ 2.816 = 9.81 m/s². Spread check for 0.300 m: trials 21.94, 22.03 and 21.99 s differ by at most 0.09 s, under the 0.3 s limit, so no fourth trial was needed. The consistent values support the text's explanation that T² is proportional to L for small angles.
🧩Section 3 · DoPractice, demonstrate, and explain
Lab record (representation): Carry out the procedure under supervision with the safety rules in place. Record, for each of four lengths: L to 0.001 m, measured from the pivot to the center of the bob (measure string length and bob diameter, then add half the diameter); three times for 20 oscillations; the spread; the mean; T; T². Plot T² against L, draw the best-fit line and calculate g from its slope. Then repeat one length with a different mass and one length at a 20° amplitude, with three trials each, and record whether the mean time for 20 oscillations changed by more than your trial spread (equivalently, whether the period changed by more than the spread divided by 20). A result that supports the text's model: T² values that lie close to a straight line through the origin, and a slope near 4.0 s²/m, which corresponds to g of about 9.8 m/s².
Independent performance: Write an analysis of 400 to 550 words evaluating the handout. Success criteria: (1) one important distinction the author makes, quoted and explained; (2) at least two gaps or inconsistencies, each cited; (3) an objective summary of the central conclusion in simpler but accurate terms; (4) your own results analyzed using the text's explanation, with every calculation shown; (5) a statement of what your extra mass and amplitude trials show and what they cannot show; (6) the results you report are your own measurements, not the sample data.
✅Section 4 · Check8-question lesson practice test
An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.
Problem 1
The handout distinguishes a complete oscillation from a single swing. Explain why this distinction matters to the result.
Show worked solution
A complete oscillation is there and back to the same point moving the same way; a single swing is only one side to the other, half an oscillation. If a student timed swings, every T would be half its true value, T squared would be a quarter, and g = 4 pi squared L / T squared would come out four times too large, about 39 m/s squared instead of about 9.8.
Problem 2
Cite the inconsistency between the Background and procedure step 1, and explain its effect on a single-point calculation of g.
Show worked solution
The Background defines L 'from the pivot to the center of mass of the bob', but step 1 says to measure 'the string length.' For a bob of radius 1.0 cm these differ by 0.010 m. Using 0.290 m instead of 0.300 m with T squared = 1.209 gives g = 39.478 times 0.290 divided by 1.209, about 9.47 m/s squared, more than 3 percent below 9.81.
Problem 3
The text says the period 'does not depend on how far it swings.' Is this accurate? Use the text itself in your answer.
Show worked solution
Not exactly. The text states the formula only for a pendulum 'swinging through a small angle' and limits the release angle to 10 degrees, which would be unnecessary if amplitude never mattered. In fact the period grows slightly with amplitude, about 0.2 percent longer than the small-angle formula at 10 degrees. The accurate statement is that for small angles the period is nearly independent of amplitude.
Problem 4
Identify a gap in the evidence for the claim that 'mass had no effect on the period.'
Show worked solution
The procedure uses a single bob, and the sample results give one set of times per length. To support the claim the text would need periods measured with two or more masses at the same length and angle. The claim matches the ideal model, but the text asserts it without data, so it is a gap.
Problem 5
Determine the central conclusion of the handout and paraphrase it in simpler but still accurate terms.
Show worked solution
Central conclusion: graphing the square of the period against the length gives a straight line whose slope is 4 pi squared divided by g, so g can be found from the slope. Paraphrase: for small swings, the squared time of a back-and-forth swing grows in proportion to the pendulum's length, and the rate of that growth depends only on gravity, so measuring the line's steepness measures gravity.
Problem 6
Explain the purpose of two steps in the procedure: timing 20 oscillations, and starting the watch at the lowest point.
Show worked solution
Timing 20 oscillations spreads the human reaction-time error of starting and stopping the watch over 20 periods, so the error in each T is one-twentieth as large. Starting at the lowest point uses the moment when the bob moves fastest, so the instant it passes the mark is sharpest and easiest to judge.
Problem 7
Using the sample data at 0.700 m, compute T, T squared and g.
Show worked solution
T = 33.560 divided by 20 = 1.678 s. T squared = 1.678 squared, about 2.816 s squared. g = 4 pi squared times L divided by T squared = 39.478 times 0.700 divided by 2.816, which is 27.635 divided by 2.816, about 9.81 m/s squared.
Problem 8
If every length had been measured to the string only, 0.010 m too short, would the slope method still give g = 9.81 m/s squared? Explain from the text's explanation.
Show worked solution
Yes. The text explains that g comes from the slope of T squared against L. Shortening every L by the same 0.010 m shifts each point sideways by the same amount, which moves the line but does not change its steepness, so the slope stays about 4.023 s squared per meter and g stays 9.81 m/s squared; the offset appears as a nonzero intercept instead. This holds only if the slope is taken between data points or from a best-fit line with its own intercept: a line forced through the origin, or a calculation from a single point, would give a low g.