Grade 1 · MathematicsAbout 90 minutes
MathematicsGrade 1About 90 minutes

Solve joining, separating, and comparing stories

Suggested multi-session teaching plan.

Ohio learning standards this draft targets

math-2017:1.OA.1

Read the standard text

math-2017:1.OA.1 Use addition and subtraction within 20 to solve word problems involving situations of adding to, taking from, putting together, taking apart and comparing, with unknowns in all positions, e.g., by using objects, drawings, and equations with a symbol for the unknown number to represent the problem. See Table 1, page 94.

Provisional targets. Clause-by-clause educational review is still pending.

Section 1 · LearnLearn the idea
Six cards can be paired in each row. Four Ana cards remain unpaired, so the difference is four cards, not ten.Six cards can be paired in each row. Four Ana cards remain unpaired, so the difference is four cards, not ten.Ana: ten cardsBo: six cards
Six cards can be paired in each row. Four Ana cards remain unpaired, so the difference is four cards, not ten.

Learning goal: Solve addition and subtraction stories within twenty with the unknown in different positions. Represent the actual relationship with objects, drawings and an equation containing a box for the unknown. Do not choose an operation merely because a story contains the word more or left; identify what is known and what the question asks.

Start with a joining story: eight children are at a table and five join them. The starting amount and change are known, but the result is unknown. Draw eight marks, then five more, and write 8 + 5 = □. The total is thirteen. Label every amount with the counted unit, children, so a mark does not become an unlabeled decoration.

Move the unknown. Eight children are at the table; some join; now there are thirteen. The equation is 8 + □ = 13, and the question asks how many joined. Count on from eight to thirteen or match the two groups to find five. If some children were there first, five joined and thirteen are now there, write □ + 5 = 13. The starting amount is eight. All three versions describe a joining relationship but ask for different amounts.

For taking-from stories, distinguish starting amount, removed amount and remainder. With fourteen counters and six removed, 14 − 6 = □ asks for the remaining eight. In 14 − □ = 8, the removed part is unknown. In □ − 6 = 8, the starting amount is unknown. Act out the complete story and check the result by rebuilding the starting collection.

Putting-together and taking-apart stories can concern parts present at the same time rather than a change over time. Seven red beads and four blue beads make eleven beads. If eleven beads include seven red beads, four are blue. The total and two parts remain the relevant quantities even when nobody arrives or leaves.

Comparison asks how much greater or smaller one amount is than another. If one group has twelve cards and another has nine, align nine pairs and observe three unmatched cards. The difference is three cards. If a group has three more than a group of nine, the larger amount is twelve; if twelve is three more than another amount, that smaller amount is nine. The comparison diagram shows two aligned groups, and the difference counts unmatched objects rather than the entire longer group.

Section 2 · ModelWork through the examples

Worked example 1: Unknown change. A box contains six blocks and later contains fifteen after blocks are added. Draw six known blocks and continue adding until fifteen. Nine were added, so 6 + 9 = 15. The answer is not fifteen because the question asks for the change.

Worked example 2: Unknown start. A child gives away four stickers and has seven left. Rebuild the earlier amount by joining four given-away stickers with seven remaining stickers. Eleven were present at first: 11 − 4 = 7. Check both the story and the equation.

Worked example 3: Compare without moving objects. Ana has ten cards and Bo has six. Pair six from each group. Ana’s four unpaired cards show the difference: ten is four more than six. Neither child has to give cards away for a subtraction comparison to be useful.

Section 3 · DoPractice, demonstrate, and explain

Guided practice: Rewrite one joining and one taking-from story three ways so the start, change and result are each unknown in turn. Use counters to justify the equations. Next describe part-part-total and comparison situations, including a larger amount, smaller amount and difference unknown in separate examples. Keep all quantities within twenty.

Independent evidence: Solve the varied practice problems below and create a drawing for each. Write an equation with a box in the position representing the actual unknown before filling it. Ask a partner to retell the situation from the drawing. Repeat across days with all situation types; one result-unknown addition example does not establish this broad target.

Scoring and feedback: Award separate credit for a correct relationship/model, equation and answer with its unit. If a learner always places the box after the equal sign, compare two versions of the same story and point to the information that changed. If the comparison answer is the larger total, return to matched and unmatched objects. Check an unknown starting amount by acting out the whole story again.

Section 4 · Check8-question lesson practice test

An adult may read the prompts aloud. Answer independently with words, objects, drawings or a demonstration before opening the answer guide. Award 1 point for a correct result or claim and 1 point for a matching explanation or demonstration; where a question asks only for a result (a corrected sentence, a spelling, a count), a fully correct result earns both points, and the answer guide shows what a complete response contains. Record prompting separately. The total (two points per question) is local practice feedback, not an Ohio proficiency level.

Problem 1

Seven blocks are in a box. Some more are added, and now there are fifteen. How many were added? Write an equation with a box for the unknown.

Show worked solution

Eight blocks; 7 + □ = 15, so □ = 8. The unknown is the added amount. 15 − 7 = □ is also a correct way to find it.

Problem 2

Some stickers were on a sheet. Seven were given away and six are left. How many were there at first? Write an equation with a box for the unknown.

Show worked solution

Thirteen stickers; □ − 7 = 6. Rejoin the seven given away and the six left to check; 6 + 7 = □ finds the same start.

Problem 3

Sixteen birds sat on a wire. Some flew away, and nine are left. How many flew away?

Show worked solution

Seven birds; 16 − □ = 9, so □ = 7. The unknown is the part taken away. 9 + □ = 16 is also correct.

Problem 4

A tray has eighteen beads. Seven are red and the rest are blue. How many are blue?

Show worked solution

Eleven beads; 7 + □ = 18 or 18 − 7 = □. The two colors are parts of the same total.

Problem 5

Maya has eleven cards and Leo has six. How many more cards does Maya have than Leo?

Show worked solution

Five cards; 6 + □ = 11 or 11 − 6 = □. After pairing six cards from each child, five of Maya’s cards are unmatched.

Problem 6

Leo has five cards. Maya has seven more cards than Leo. How many cards does Maya have?

Show worked solution

Twelve cards; 5 + 7 = □. Here the larger amount, not the difference, is unknown.

Problem 7

Maya has seventeen cards, which is five more than Leo has. How many cards does Leo have?

Show worked solution

Twelve cards; □ + 5 = 17 or 17 − 5 = □. Check that seventeen is five more than twelve. Adding five to seventeen would follow the word “more” instead of the story.

Problem 8

Leo has four fewer cards than Maya. Maya has thirteen cards. How many cards does Leo have?

Show worked solution

Nine cards; 13 − 4 = □ or □ + 4 = 13. Check that nine is four fewer than thirteen.